Users' Mathboxes Mathbox for Peter Mazsa < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >   Mathboxes  >  relcnveq Structured version   Visualization version   GIF version

Theorem relcnveq 35594
Description: Two ways of saying a relation is symmetric. (Contributed by Peter Mazsa, 23-Aug-2018.)
Assertion
Ref Expression
relcnveq (Rel 𝑅 → (𝑅𝑅𝑅 = 𝑅))

Proof of Theorem relcnveq
Dummy variables 𝑥 𝑦 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 eqcom 2828 . 2 (𝑅 = 𝑅𝑅 = 𝑅)
2 relcnveq3 35593 . . 3 (Rel 𝑅 → (𝑅 = 𝑅 ↔ ∀𝑥𝑦(𝑥𝑅𝑦𝑦𝑅𝑥)))
3 cnvsym 5974 . . 3 (𝑅𝑅 ↔ ∀𝑥𝑦(𝑥𝑅𝑦𝑦𝑅𝑥))
42, 3syl6bbr 291 . 2 (Rel 𝑅 → (𝑅 = 𝑅𝑅𝑅))
51, 4syl5rbbr 288 1 (Rel 𝑅 → (𝑅𝑅𝑅 = 𝑅))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 208  wal 1535   = wceq 1537  wss 3936   class class class wbr 5066  ccnv 5554  Rel wrel 5560
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1970  ax-7 2015  ax-8 2116  ax-9 2124  ax-10 2145  ax-11 2161  ax-12 2177  ax-ext 2793  ax-sep 5203  ax-nul 5210  ax-pr 5330
This theorem depends on definitions:  df-bi 209  df-an 399  df-or 844  df-3an 1085  df-tru 1540  df-ex 1781  df-nf 1785  df-sb 2070  df-mo 2622  df-eu 2654  df-clab 2800  df-cleq 2814  df-clel 2893  df-nfc 2963  df-rab 3147  df-v 3496  df-dif 3939  df-un 3941  df-in 3943  df-ss 3952  df-nul 4292  df-if 4468  df-sn 4568  df-pr 4570  df-op 4574  df-br 5067  df-opab 5129  df-xp 5561  df-rel 5562  df-cnv 5563
This theorem is referenced by:  relcnveq4  35596  cnvcosseq  35697  dfsymrel4  35802
  Copyright terms: Public domain W3C validator