Theorem simplbi2comg 1493

Description: Implication form of simplbi2com 1494. (Contributed by Alan Sare, 22-Jul-2012.)

Assertion

Ref	Expression
simplbi2comg	|- ( ( ph <-> ( ps /\ ch ) ) -> ( ch -> ( ps -> ph ) ) )

Proof of Theorem simplbi2comg

Step	Hyp	Ref	Expression
1		biimpr 130	. 2 |- ( ( ph <-> ( ps /\ ch ) ) -> ( ( ps /\ ch ) -> ph ) )
2	1	expcomd 1491	1 |- ( ( ph <-> ( ps /\ ch ) ) -> ( ch -> ( ps -> ph ) ) )

This proof depends on syntax axioms:   -> wi 4   /\ wa 104   <-> wb 105

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108

This proof depends on definitions:  df-bi 117

This theorem is used by: (None)