Theorem expdcom 1492

Description: Commuted form of expd 258. (Contributed by Alan Sare, 18-Mar-2012.)

Hypothesis

Ref	Expression
expdcom.1	|- ( ph -> ( ( ps /\ ch ) -> th ) )

Assertion

Ref	Expression
expdcom	|- ( ps -> ( ch -> ( ph -> th ) ) )

Proof of Theorem expdcom

Step	Hyp	Ref	Expression
1		expdcom.1	. . 3 |- ( ph -> ( ( ps /\ ch ) -> th ) )
2	1	expd 258	. 2 |- ( ph -> ( ps -> ( ch -> th ) ) )
3	2	com3l 81	1 |- ( ps -> ( ch -> ( ph -> th ) ) )

This proof depends on syntax axioms:   -> wi 4   /\ wa 104

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia3 108

This theorem is used by:  nndi  6759  nnmass  6760  mulexp  11015  expadd  11018  expmul  11021  usgredg2vlem2  16464