Theorem expcomd 1487

Description: Deduction form of expcom 116. (Contributed by Alan Sare, 22-Jul-2012.)

Hypothesis

Ref	Expression
expcomd.1	|- ( ph -> ( ( ps /\ ch ) -> th ) )

Assertion

Ref	Expression
expcomd	|- ( ph -> ( ch -> ( ps -> th ) ) )

Proof of Theorem expcomd

Step	Hyp	Ref	Expression
1		expcomd.1	. . 3 |- ( ph -> ( ( ps /\ ch ) -> th ) )
2	1	expd 258	. 2 |- ( ph -> ( ps -> ( ch -> th ) ) )
3	2	com23 78	1 |- ( ph -> ( ch -> ( ps -> th ) ) )

Syntax hints:   -> wi 4   /\ wa 104

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia3 108

This theorem is referenced by:  simplbi2comg  1489  2moswapdc  2173  indifdir  3481  reupick  3509  issod  4445  poxp  6441  smores2  6538  smoiun  6545  mapxpen  7114  f1dmvrnfibi  7224  recexprlemm  7955  ltleletr  8371  fzind  9711  iccid  10277  ssfzo12bi  10592  pfxccatin12lem2  11448  swrdccat  11452  dvdsabseq  12558  divalgb  12636  cncongr1  12825  difsqpwdvds  13061  lss1d  14657  txlm  15270  blsscls2  15484  metcnpi3  15508  clwwlknonex2lem2  16559