Theorem expcomd 1441

Description: Deduction form of expcom 116. (Contributed by Alan Sare, 22-Jul-2012.)

Hypothesis

Ref	Expression
expcomd.1	|- ( ph -> ( ( ps /\ ch ) -> th ) )

Assertion

Ref	Expression
expcomd	|- ( ph -> ( ch -> ( ps -> th ) ) )

Proof of Theorem expcomd

Step	Hyp	Ref	Expression
1		expcomd.1	. . 3 |- ( ph -> ( ( ps /\ ch ) -> th ) )
2	1	expd 258	. 2 |- ( ph -> ( ps -> ( ch -> th ) ) )
3	2	com23 78	1 |- ( ph -> ( ch -> ( ps -> th ) ) )

Syntax hints:   -> wi 4   /\ wa 104

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia3 108

This theorem is referenced by:  simplbi2comg  1443  2moswapdc  2116  indifdir  3392  reupick  3420  issod  4320  poxp  6233  smores2  6295  smoiun  6302  mapxpen  6848  f1dmvrnfibi  6943  recexprlemm  7623  ltleletr  8039  fzind  9368  iccid  9925  ssfzo12bi  10225  dvdsabseq  11853  divalgb  11930  cncongr1  12103  difsqpwdvds  12337  txlm  13782  blsscls2  13996  metcnpi3  14020