Theorem 3jaao 1349

Description: Inference conjoining and disjoining the antecedents of three implications. (Contributed by Jeff Hankins, 15-Aug-2009.) (Proof shortened by Andrew Salmon, 13-May-2011.)

Hypotheses

Ref	Expression
3jaao.1	⊢ (𝜑 → (𝜓 → 𝜒))
3jaao.2	⊢ (𝜃 → (𝜏 → 𝜒))
3jaao.3	⊢ (𝜂 → (𝜁 → 𝜒))

Assertion

Ref	Expression
3jaao	⊢ ((𝜑 ∧ 𝜃 ∧ 𝜂) → ((𝜓 ∨ 𝜏 ∨ 𝜁) → 𝜒))

Proof of Theorem 3jaao

Step	Hyp	Ref	Expression
1		3jaao.1	. . 3 ⊢ (𝜑 → (𝜓 → 𝜒))
2	1	3ad2ant1 1049	. 2 ⊢ ((𝜑 ∧ 𝜃 ∧ 𝜂) → (𝜓 → 𝜒))
3		3jaao.2	. . 3 ⊢ (𝜃 → (𝜏 → 𝜒))
4	3	3ad2ant2 1050	. 2 ⊢ ((𝜑 ∧ 𝜃 ∧ 𝜂) → (𝜏 → 𝜒))
5		3jaao.3	. . 3 ⊢ (𝜂 → (𝜁 → 𝜒))
6	5	3ad2ant3 1051	. 2 ⊢ ((𝜑 ∧ 𝜃 ∧ 𝜂) → (𝜁 → 𝜒))
7	2, 4, 6	3jaod 1345	1 ⊢ ((𝜑 ∧ 𝜃 ∧ 𝜂) → ((𝜓 ∨ 𝜏 ∨ 𝜁) → 𝜒))

This proof depends on syntax axioms:   → wi 4   ∨ w3o 1008   ∧ w3a 1009

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 721

This proof depends on definitions:  df-bi 117  df-3or 1010  df-3an 1011

This theorem is used by: (None)