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| Type | Label | Description |
|---|---|---|
| Statement | ||
| Theorem | syl133anc 1301 | Syllogism combined with contraction. (Contributed by NM, 11-Mar-2012.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → 𝜃) & ⊢ (𝜑 → 𝜏) & ⊢ (𝜑 → 𝜂) & ⊢ (𝜑 → 𝜁) & ⊢ (𝜑 → 𝜎) & ⊢ ((𝜓 ∧ (𝜒 ∧ 𝜃 ∧ 𝜏) ∧ (𝜂 ∧ 𝜁 ∧ 𝜎)) → 𝜌) ⇒ ⊢ (𝜑 → 𝜌) | ||
| Theorem | syl313anc 1302 | Syllogism combined with contraction. (Contributed by NM, 11-Mar-2012.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → 𝜃) & ⊢ (𝜑 → 𝜏) & ⊢ (𝜑 → 𝜂) & ⊢ (𝜑 → 𝜁) & ⊢ (𝜑 → 𝜎) & ⊢ (((𝜓 ∧ 𝜒 ∧ 𝜃) ∧ 𝜏 ∧ (𝜂 ∧ 𝜁 ∧ 𝜎)) → 𝜌) ⇒ ⊢ (𝜑 → 𝜌) | ||
| Theorem | syl331anc 1303 | Syllogism combined with contraction. (Contributed by NM, 11-Mar-2012.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → 𝜃) & ⊢ (𝜑 → 𝜏) & ⊢ (𝜑 → 𝜂) & ⊢ (𝜑 → 𝜁) & ⊢ (𝜑 → 𝜎) & ⊢ (((𝜓 ∧ 𝜒 ∧ 𝜃) ∧ (𝜏 ∧ 𝜂 ∧ 𝜁) ∧ 𝜎) → 𝜌) ⇒ ⊢ (𝜑 → 𝜌) | ||
| Theorem | syl223anc 1304 | Syllogism combined with contraction. (Contributed by NM, 11-Mar-2012.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → 𝜃) & ⊢ (𝜑 → 𝜏) & ⊢ (𝜑 → 𝜂) & ⊢ (𝜑 → 𝜁) & ⊢ (𝜑 → 𝜎) & ⊢ (((𝜓 ∧ 𝜒) ∧ (𝜃 ∧ 𝜏) ∧ (𝜂 ∧ 𝜁 ∧ 𝜎)) → 𝜌) ⇒ ⊢ (𝜑 → 𝜌) | ||
| Theorem | syl232anc 1305 | Syllogism combined with contraction. (Contributed by NM, 11-Mar-2012.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → 𝜃) & ⊢ (𝜑 → 𝜏) & ⊢ (𝜑 → 𝜂) & ⊢ (𝜑 → 𝜁) & ⊢ (𝜑 → 𝜎) & ⊢ (((𝜓 ∧ 𝜒) ∧ (𝜃 ∧ 𝜏 ∧ 𝜂) ∧ (𝜁 ∧ 𝜎)) → 𝜌) ⇒ ⊢ (𝜑 → 𝜌) | ||
| Theorem | syl322anc 1306 | Syllogism combined with contraction. (Contributed by NM, 11-Mar-2012.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → 𝜃) & ⊢ (𝜑 → 𝜏) & ⊢ (𝜑 → 𝜂) & ⊢ (𝜑 → 𝜁) & ⊢ (𝜑 → 𝜎) & ⊢ (((𝜓 ∧ 𝜒 ∧ 𝜃) ∧ (𝜏 ∧ 𝜂) ∧ (𝜁 ∧ 𝜎)) → 𝜌) ⇒ ⊢ (𝜑 → 𝜌) | ||
| Theorem | syl233anc 1307 | Syllogism combined with contraction. (Contributed by NM, 11-Mar-2012.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → 𝜃) & ⊢ (𝜑 → 𝜏) & ⊢ (𝜑 → 𝜂) & ⊢ (𝜑 → 𝜁) & ⊢ (𝜑 → 𝜎) & ⊢ (𝜑 → 𝜌) & ⊢ (((𝜓 ∧ 𝜒) ∧ (𝜃 ∧ 𝜏 ∧ 𝜂) ∧ (𝜁 ∧ 𝜎 ∧ 𝜌)) → 𝜇) ⇒ ⊢ (𝜑 → 𝜇) | ||
| Theorem | syl323anc 1308 | Syllogism combined with contraction. (Contributed by NM, 11-Mar-2012.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → 𝜃) & ⊢ (𝜑 → 𝜏) & ⊢ (𝜑 → 𝜂) & ⊢ (𝜑 → 𝜁) & ⊢ (𝜑 → 𝜎) & ⊢ (𝜑 → 𝜌) & ⊢ (((𝜓 ∧ 𝜒 ∧ 𝜃) ∧ (𝜏 ∧ 𝜂) ∧ (𝜁 ∧ 𝜎 ∧ 𝜌)) → 𝜇) ⇒ ⊢ (𝜑 → 𝜇) | ||
| Theorem | syl332anc 1309 | Syllogism combined with contraction. (Contributed by NM, 11-Mar-2012.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → 𝜃) & ⊢ (𝜑 → 𝜏) & ⊢ (𝜑 → 𝜂) & ⊢ (𝜑 → 𝜁) & ⊢ (𝜑 → 𝜎) & ⊢ (𝜑 → 𝜌) & ⊢ (((𝜓 ∧ 𝜒 ∧ 𝜃) ∧ (𝜏 ∧ 𝜂 ∧ 𝜁) ∧ (𝜎 ∧ 𝜌)) → 𝜇) ⇒ ⊢ (𝜑 → 𝜇) | ||
| Theorem | syl333anc 1310 | A syllogism inference combined with contraction. (Contributed by NM, 10-Mar-2012.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → 𝜃) & ⊢ (𝜑 → 𝜏) & ⊢ (𝜑 → 𝜂) & ⊢ (𝜑 → 𝜁) & ⊢ (𝜑 → 𝜎) & ⊢ (𝜑 → 𝜌) & ⊢ (𝜑 → 𝜇) & ⊢ (((𝜓 ∧ 𝜒 ∧ 𝜃) ∧ (𝜏 ∧ 𝜂 ∧ 𝜁) ∧ (𝜎 ∧ 𝜌 ∧ 𝜇)) → 𝜆) ⇒ ⊢ (𝜑 → 𝜆) | ||
| Theorem | syl3an1 1311 | A syllogism inference. (Contributed by NM, 22-Aug-1995.) |
| ⊢ (𝜑 → 𝜓) & ⊢ ((𝜓 ∧ 𝜒 ∧ 𝜃) → 𝜏) ⇒ ⊢ ((𝜑 ∧ 𝜒 ∧ 𝜃) → 𝜏) | ||
| Theorem | syl3an2 1312 | A syllogism inference. (Contributed by NM, 22-Aug-1995.) |
| ⊢ (𝜑 → 𝜒) & ⊢ ((𝜓 ∧ 𝜒 ∧ 𝜃) → 𝜏) ⇒ ⊢ ((𝜓 ∧ 𝜑 ∧ 𝜃) → 𝜏) | ||
| Theorem | syl3an3 1313 | A syllogism inference. (Contributed by NM, 22-Aug-1995.) |
| ⊢ (𝜑 → 𝜃) & ⊢ ((𝜓 ∧ 𝜒 ∧ 𝜃) → 𝜏) ⇒ ⊢ ((𝜓 ∧ 𝜒 ∧ 𝜑) → 𝜏) | ||
| Theorem | syl3an1b 1314 | A syllogism inference. (Contributed by NM, 22-Aug-1995.) |
| ⊢ (𝜑 ↔ 𝜓) & ⊢ ((𝜓 ∧ 𝜒 ∧ 𝜃) → 𝜏) ⇒ ⊢ ((𝜑 ∧ 𝜒 ∧ 𝜃) → 𝜏) | ||
| Theorem | syl3an2b 1315 | A syllogism inference. (Contributed by NM, 22-Aug-1995.) |
| ⊢ (𝜑 ↔ 𝜒) & ⊢ ((𝜓 ∧ 𝜒 ∧ 𝜃) → 𝜏) ⇒ ⊢ ((𝜓 ∧ 𝜑 ∧ 𝜃) → 𝜏) | ||
| Theorem | syl3an3b 1316 | A syllogism inference. (Contributed by NM, 22-Aug-1995.) |
| ⊢ (𝜑 ↔ 𝜃) & ⊢ ((𝜓 ∧ 𝜒 ∧ 𝜃) → 𝜏) ⇒ ⊢ ((𝜓 ∧ 𝜒 ∧ 𝜑) → 𝜏) | ||
| Theorem | syl3an1br 1317 | A syllogism inference. (Contributed by NM, 22-Aug-1995.) |
| ⊢ (𝜓 ↔ 𝜑) & ⊢ ((𝜓 ∧ 𝜒 ∧ 𝜃) → 𝜏) ⇒ ⊢ ((𝜑 ∧ 𝜒 ∧ 𝜃) → 𝜏) | ||
| Theorem | syl3an2br 1318 | A syllogism inference. (Contributed by NM, 22-Aug-1995.) |
| ⊢ (𝜒 ↔ 𝜑) & ⊢ ((𝜓 ∧ 𝜒 ∧ 𝜃) → 𝜏) ⇒ ⊢ ((𝜓 ∧ 𝜑 ∧ 𝜃) → 𝜏) | ||
| Theorem | syl3an3br 1319 | A syllogism inference. (Contributed by NM, 22-Aug-1995.) |
| ⊢ (𝜃 ↔ 𝜑) & ⊢ ((𝜓 ∧ 𝜒 ∧ 𝜃) → 𝜏) ⇒ ⊢ ((𝜓 ∧ 𝜒 ∧ 𝜑) → 𝜏) | ||
| Theorem | syl3an 1320 | A triple syllogism inference. (Contributed by NM, 13-May-2004.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜒 → 𝜃) & ⊢ (𝜏 → 𝜂) & ⊢ ((𝜓 ∧ 𝜃 ∧ 𝜂) → 𝜁) ⇒ ⊢ ((𝜑 ∧ 𝜒 ∧ 𝜏) → 𝜁) | ||
| Theorem | syl3anb 1321 | A triple syllogism inference. (Contributed by NM, 15-Oct-2005.) |
| ⊢ (𝜑 ↔ 𝜓) & ⊢ (𝜒 ↔ 𝜃) & ⊢ (𝜏 ↔ 𝜂) & ⊢ ((𝜓 ∧ 𝜃 ∧ 𝜂) → 𝜁) ⇒ ⊢ ((𝜑 ∧ 𝜒 ∧ 𝜏) → 𝜁) | ||
| Theorem | syl3anbr 1322 | A triple syllogism inference. (Contributed by NM, 29-Dec-2011.) |
| ⊢ (𝜓 ↔ 𝜑) & ⊢ (𝜃 ↔ 𝜒) & ⊢ (𝜂 ↔ 𝜏) & ⊢ ((𝜓 ∧ 𝜃 ∧ 𝜂) → 𝜁) ⇒ ⊢ ((𝜑 ∧ 𝜒 ∧ 𝜏) → 𝜁) | ||
| Theorem | syld3an3 1323 | A syllogism inference. (Contributed by NM, 20-May-2007.) |
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜃) & ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜃) → 𝜏) ⇒ ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜏) | ||
| Theorem | syld3an1 1324 | A syllogism inference. (Contributed by NM, 7-Jul-2008.) |
| ⊢ ((𝜒 ∧ 𝜓 ∧ 𝜃) → 𝜑) & ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜃) → 𝜏) ⇒ ⊢ ((𝜒 ∧ 𝜓 ∧ 𝜃) → 𝜏) | ||
| Theorem | syld3an2 1325 | A syllogism inference. (Contributed by NM, 20-May-2007.) |
| ⊢ ((𝜑 ∧ 𝜒 ∧ 𝜃) → 𝜓) & ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜃) → 𝜏) ⇒ ⊢ ((𝜑 ∧ 𝜒 ∧ 𝜃) → 𝜏) | ||
| Theorem | syl3anl1 1326 | A syllogism inference. (Contributed by NM, 24-Feb-2005.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (((𝜓 ∧ 𝜒 ∧ 𝜃) ∧ 𝜏) → 𝜂) ⇒ ⊢ (((𝜑 ∧ 𝜒 ∧ 𝜃) ∧ 𝜏) → 𝜂) | ||
| Theorem | syl3anl2 1327 | A syllogism inference. (Contributed by NM, 24-Feb-2005.) |
| ⊢ (𝜑 → 𝜒) & ⊢ (((𝜓 ∧ 𝜒 ∧ 𝜃) ∧ 𝜏) → 𝜂) ⇒ ⊢ (((𝜓 ∧ 𝜑 ∧ 𝜃) ∧ 𝜏) → 𝜂) | ||
| Theorem | syl3anl3 1328 | A syllogism inference. (Contributed by NM, 24-Feb-2005.) |
| ⊢ (𝜑 → 𝜃) & ⊢ (((𝜓 ∧ 𝜒 ∧ 𝜃) ∧ 𝜏) → 𝜂) ⇒ ⊢ (((𝜓 ∧ 𝜒 ∧ 𝜑) ∧ 𝜏) → 𝜂) | ||
| Theorem | syl3anl 1329 | A triple syllogism inference. (Contributed by NM, 24-Dec-2006.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜒 → 𝜃) & ⊢ (𝜏 → 𝜂) & ⊢ (((𝜓 ∧ 𝜃 ∧ 𝜂) ∧ 𝜁) → 𝜎) ⇒ ⊢ (((𝜑 ∧ 𝜒 ∧ 𝜏) ∧ 𝜁) → 𝜎) | ||
| Theorem | syl3anr1 1330 | A syllogism inference. (Contributed by NM, 31-Jul-2007.) |
| ⊢ (𝜑 → 𝜓) & ⊢ ((𝜒 ∧ (𝜓 ∧ 𝜃 ∧ 𝜏)) → 𝜂) ⇒ ⊢ ((𝜒 ∧ (𝜑 ∧ 𝜃 ∧ 𝜏)) → 𝜂) | ||
| Theorem | syl3anr2 1331 | A syllogism inference. (Contributed by NM, 1-Aug-2007.) |
| ⊢ (𝜑 → 𝜃) & ⊢ ((𝜒 ∧ (𝜓 ∧ 𝜃 ∧ 𝜏)) → 𝜂) ⇒ ⊢ ((𝜒 ∧ (𝜓 ∧ 𝜑 ∧ 𝜏)) → 𝜂) | ||
| Theorem | syl3anr3 1332 | A syllogism inference. (Contributed by NM, 23-Aug-2007.) |
| ⊢ (𝜑 → 𝜏) & ⊢ ((𝜒 ∧ (𝜓 ∧ 𝜃 ∧ 𝜏)) → 𝜂) ⇒ ⊢ ((𝜒 ∧ (𝜓 ∧ 𝜃 ∧ 𝜑)) → 𝜂) | ||
| Theorem | syldbl2 1333 | Stacked hypotheseis implies goal. (Contributed by Stanislas Polu, 9-Mar-2020.) |
| ⊢ ((𝜑 ∧ 𝜓) → (𝜓 → 𝜃)) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜃) | ||
| Theorem | 3impdi 1334 | Importation inference (undistribute conjunction). (Contributed by NM, 14-Aug-1995.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜑 ∧ 𝜒)) → 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜃) | ||
| Theorem | 3impdir 1335 | Importation inference (undistribute conjunction). (Contributed by NM, 20-Aug-1995.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜓)) → 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜒 ∧ 𝜓) → 𝜃) | ||
| Theorem | 3anidm12 1336 | Inference from idempotent law for conjunction. (Contributed by NM, 7-Mar-2008.) |
| ⊢ ((𝜑 ∧ 𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜒) | ||
| Theorem | 3anidm13 1337 | Inference from idempotent law for conjunction. (Contributed by NM, 7-Mar-2008.) |
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜑) → 𝜒) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜒) | ||
| Theorem | 3anidm23 1338 | Inference from idempotent law for conjunction. (Contributed by NM, 1-Feb-2007.) |
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜓) → 𝜒) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜒) | ||
| Theorem | syl2an3an 1339 | syl3an 1320 with antecedents in standard conjunction form. (Contributed by Alan Sare, 31-Aug-2016.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ (𝜃 → 𝜏) & ⊢ ((𝜓 ∧ 𝜒 ∧ 𝜏) → 𝜂) ⇒ ⊢ ((𝜑 ∧ 𝜃) → 𝜂) | ||
| Theorem | syl2an23an 1340 | Deduction related to syl3an 1320 with antecedents in standard conjunction form. (Contributed by Alan Sare, 31-Aug-2016.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ ((𝜃 ∧ 𝜑) → 𝜏) & ⊢ ((𝜓 ∧ 𝜒 ∧ 𝜏) → 𝜂) ⇒ ⊢ ((𝜃 ∧ 𝜑) → 𝜂) | ||
| Theorem | 3ori 1341 | Infer implication from triple disjunction. (Contributed by NM, 26-Sep-2006.) |
| ⊢ (𝜑 ∨ 𝜓 ∨ 𝜒) ⇒ ⊢ ((¬ 𝜑 ∧ ¬ 𝜓) → 𝜒) | ||
| Theorem | 3jao 1342 | Disjunction of 3 antecedents. (Contributed by NM, 8-Apr-1994.) |
| ⊢ (((𝜑 → 𝜓) ∧ (𝜒 → 𝜓) ∧ (𝜃 → 𝜓)) → ((𝜑 ∨ 𝜒 ∨ 𝜃) → 𝜓)) | ||
| Theorem | 3jaob 1343 | Disjunction of 3 antecedents. (Contributed by NM, 13-Sep-2011.) |
| ⊢ (((𝜑 ∨ 𝜒 ∨ 𝜃) → 𝜓) ↔ ((𝜑 → 𝜓) ∧ (𝜒 → 𝜓) ∧ (𝜃 → 𝜓))) | ||
| Theorem | 3jaoi 1344 | Disjunction of 3 antecedents (inference). (Contributed by NM, 12-Sep-1995.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜒 → 𝜓) & ⊢ (𝜃 → 𝜓) ⇒ ⊢ ((𝜑 ∨ 𝜒 ∨ 𝜃) → 𝜓) | ||
| Theorem | 3jaod 1345 | Disjunction of 3 antecedents (deduction). (Contributed by NM, 14-Oct-2005.) |
| ⊢ (𝜑 → (𝜓 → 𝜒)) & ⊢ (𝜑 → (𝜃 → 𝜒)) & ⊢ (𝜑 → (𝜏 → 𝜒)) ⇒ ⊢ (𝜑 → ((𝜓 ∨ 𝜃 ∨ 𝜏) → 𝜒)) | ||
| Theorem | 3jaoian 1346 | Disjunction of 3 antecedents (inference). (Contributed by NM, 14-Oct-2005.) |
| ⊢ ((𝜑 ∧ 𝜓) → 𝜒) & ⊢ ((𝜃 ∧ 𝜓) → 𝜒) & ⊢ ((𝜏 ∧ 𝜓) → 𝜒) ⇒ ⊢ (((𝜑 ∨ 𝜃 ∨ 𝜏) ∧ 𝜓) → 𝜒) | ||
| Theorem | 3jaodan 1347 | Disjunction of 3 antecedents (deduction). (Contributed by NM, 14-Oct-2005.) |
| ⊢ ((𝜑 ∧ 𝜓) → 𝜒) & ⊢ ((𝜑 ∧ 𝜃) → 𝜒) & ⊢ ((𝜑 ∧ 𝜏) → 𝜒) ⇒ ⊢ ((𝜑 ∧ (𝜓 ∨ 𝜃 ∨ 𝜏)) → 𝜒) | ||
| Theorem | mpjao3dan 1348 | Eliminate a 3-way disjunction in a deduction. (Contributed by Thierry Arnoux, 13-Apr-2018.) |
| ⊢ ((𝜑 ∧ 𝜓) → 𝜒) & ⊢ ((𝜑 ∧ 𝜃) → 𝜒) & ⊢ ((𝜑 ∧ 𝜏) → 𝜒) & ⊢ (𝜑 → (𝜓 ∨ 𝜃 ∨ 𝜏)) ⇒ ⊢ (𝜑 → 𝜒) | ||
| Theorem | 3jaao 1349 | Inference conjoining and disjoining the antecedents of three implications. (Contributed by Jeff Hankins, 15-Aug-2009.) (Proof shortened by Andrew Salmon, 13-May-2011.) |
| ⊢ (𝜑 → (𝜓 → 𝜒)) & ⊢ (𝜃 → (𝜏 → 𝜒)) & ⊢ (𝜂 → (𝜁 → 𝜒)) ⇒ ⊢ ((𝜑 ∧ 𝜃 ∧ 𝜂) → ((𝜓 ∨ 𝜏 ∨ 𝜁) → 𝜒)) | ||
| Theorem | 3ianorr 1350 | Triple disjunction implies negated triple conjunction. (Contributed by Jim Kingdon, 23-Dec-2018.) |
| ⊢ ((¬ 𝜑 ∨ ¬ 𝜓 ∨ ¬ 𝜒) → ¬ (𝜑 ∧ 𝜓 ∧ 𝜒)) | ||
| Theorem | syl3an9b 1351 | Nested syllogism inference conjoining 3 dissimilar antecedents. (Contributed by NM, 1-May-1995.) |
| ⊢ (𝜑 → (𝜓 ↔ 𝜒)) & ⊢ (𝜃 → (𝜒 ↔ 𝜏)) & ⊢ (𝜂 → (𝜏 ↔ 𝜁)) ⇒ ⊢ ((𝜑 ∧ 𝜃 ∧ 𝜂) → (𝜓 ↔ 𝜁)) | ||
| Theorem | 3orbi123d 1352 | Deduction joining 3 equivalences to form equivalence of disjunctions. (Contributed by NM, 20-Apr-1994.) |
| ⊢ (𝜑 → (𝜓 ↔ 𝜒)) & ⊢ (𝜑 → (𝜃 ↔ 𝜏)) & ⊢ (𝜑 → (𝜂 ↔ 𝜁)) ⇒ ⊢ (𝜑 → ((𝜓 ∨ 𝜃 ∨ 𝜂) ↔ (𝜒 ∨ 𝜏 ∨ 𝜁))) | ||
| Theorem | 3anbi123d 1353 | Deduction joining 3 equivalences to form equivalence of conjunctions. (Contributed by NM, 22-Apr-1994.) |
| ⊢ (𝜑 → (𝜓 ↔ 𝜒)) & ⊢ (𝜑 → (𝜃 ↔ 𝜏)) & ⊢ (𝜑 → (𝜂 ↔ 𝜁)) ⇒ ⊢ (𝜑 → ((𝜓 ∧ 𝜃 ∧ 𝜂) ↔ (𝜒 ∧ 𝜏 ∧ 𝜁))) | ||
| Theorem | 3anbi12d 1354 | Deduction conjoining and adding a conjunct to equivalences. (Contributed by NM, 8-Sep-2006.) |
| ⊢ (𝜑 → (𝜓 ↔ 𝜒)) & ⊢ (𝜑 → (𝜃 ↔ 𝜏)) ⇒ ⊢ (𝜑 → ((𝜓 ∧ 𝜃 ∧ 𝜂) ↔ (𝜒 ∧ 𝜏 ∧ 𝜂))) | ||
| Theorem | 3anbi13d 1355 | Deduction conjoining and adding a conjunct to equivalences. (Contributed by NM, 8-Sep-2006.) |
| ⊢ (𝜑 → (𝜓 ↔ 𝜒)) & ⊢ (𝜑 → (𝜃 ↔ 𝜏)) ⇒ ⊢ (𝜑 → ((𝜓 ∧ 𝜂 ∧ 𝜃) ↔ (𝜒 ∧ 𝜂 ∧ 𝜏))) | ||
| Theorem | 3anbi23d 1356 | Deduction conjoining and adding a conjunct to equivalences. (Contributed by NM, 8-Sep-2006.) |
| ⊢ (𝜑 → (𝜓 ↔ 𝜒)) & ⊢ (𝜑 → (𝜃 ↔ 𝜏)) ⇒ ⊢ (𝜑 → ((𝜂 ∧ 𝜓 ∧ 𝜃) ↔ (𝜂 ∧ 𝜒 ∧ 𝜏))) | ||
| Theorem | 3anbi1d 1357 | Deduction adding conjuncts to an equivalence. (Contributed by NM, 8-Sep-2006.) |
| ⊢ (𝜑 → (𝜓 ↔ 𝜒)) ⇒ ⊢ (𝜑 → ((𝜓 ∧ 𝜃 ∧ 𝜏) ↔ (𝜒 ∧ 𝜃 ∧ 𝜏))) | ||
| Theorem | 3anbi2d 1358 | Deduction adding conjuncts to an equivalence. (Contributed by NM, 8-Sep-2006.) |
| ⊢ (𝜑 → (𝜓 ↔ 𝜒)) ⇒ ⊢ (𝜑 → ((𝜃 ∧ 𝜓 ∧ 𝜏) ↔ (𝜃 ∧ 𝜒 ∧ 𝜏))) | ||
| Theorem | 3anbi3d 1359 | Deduction adding conjuncts to an equivalence. (Contributed by NM, 8-Sep-2006.) |
| ⊢ (𝜑 → (𝜓 ↔ 𝜒)) ⇒ ⊢ (𝜑 → ((𝜃 ∧ 𝜏 ∧ 𝜓) ↔ (𝜃 ∧ 𝜏 ∧ 𝜒))) | ||
| Theorem | 3anim123d 1360 | Deduction joining 3 implications to form implication of conjunctions. (Contributed by NM, 24-Feb-2005.) |
| ⊢ (𝜑 → (𝜓 → 𝜒)) & ⊢ (𝜑 → (𝜃 → 𝜏)) & ⊢ (𝜑 → (𝜂 → 𝜁)) ⇒ ⊢ (𝜑 → ((𝜓 ∧ 𝜃 ∧ 𝜂) → (𝜒 ∧ 𝜏 ∧ 𝜁))) | ||
| Theorem | 3orim123d 1361 | Deduction joining 3 implications to form implication of disjunctions. (Contributed by NM, 4-Apr-1997.) |
| ⊢ (𝜑 → (𝜓 → 𝜒)) & ⊢ (𝜑 → (𝜃 → 𝜏)) & ⊢ (𝜑 → (𝜂 → 𝜁)) ⇒ ⊢ (𝜑 → ((𝜓 ∨ 𝜃 ∨ 𝜂) → (𝜒 ∨ 𝜏 ∨ 𝜁))) | ||
| Theorem | an6 1362 | Rearrangement of 6 conjuncts. (Contributed by NM, 13-Mar-1995.) |
| ⊢ (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ (𝜃 ∧ 𝜏 ∧ 𝜂)) ↔ ((𝜑 ∧ 𝜃) ∧ (𝜓 ∧ 𝜏) ∧ (𝜒 ∧ 𝜂))) | ||
| Theorem | 3an6 1363 | Analog of an4 592 for triple conjunction. (Contributed by Scott Fenton, 16-Mar-2011.) (Proof shortened by Andrew Salmon, 25-May-2011.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃) ∧ (𝜏 ∧ 𝜂)) ↔ ((𝜑 ∧ 𝜒 ∧ 𝜏) ∧ (𝜓 ∧ 𝜃 ∧ 𝜂))) | ||
| Theorem | 3or6 1364 | Analog of or4 783 for triple conjunction. (Contributed by Scott Fenton, 16-Mar-2011.) |
| ⊢ (((𝜑 ∨ 𝜓) ∨ (𝜒 ∨ 𝜃) ∨ (𝜏 ∨ 𝜂)) ↔ ((𝜑 ∨ 𝜒 ∨ 𝜏) ∨ (𝜓 ∨ 𝜃 ∨ 𝜂))) | ||
| Theorem | mp3an1 1365 | An inference based on modus ponens. (Contributed by NM, 21-Nov-1994.) |
| ⊢ 𝜑 & ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜃) ⇒ ⊢ ((𝜓 ∧ 𝜒) → 𝜃) | ||
| Theorem | mp3an2 1366 | An inference based on modus ponens. (Contributed by NM, 21-Nov-1994.) |
| ⊢ 𝜓 & ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜒) → 𝜃) | ||
| Theorem | mp3an3 1367 | An inference based on modus ponens. (Contributed by NM, 21-Nov-1994.) |
| ⊢ 𝜒 & ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜃) | ||
| Theorem | mp3an12 1368 | An inference based on modus ponens. (Contributed by NM, 13-Jul-2005.) |
| ⊢ 𝜑 & ⊢ 𝜓 & ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜃) ⇒ ⊢ (𝜒 → 𝜃) | ||
| Theorem | mp3an13 1369 | An inference based on modus ponens. (Contributed by NM, 14-Jul-2005.) |
| ⊢ 𝜑 & ⊢ 𝜒 & ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜃) ⇒ ⊢ (𝜓 → 𝜃) | ||
| Theorem | mp3an23 1370 | An inference based on modus ponens. (Contributed by NM, 14-Jul-2005.) |
| ⊢ 𝜓 & ⊢ 𝜒 & ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜃) ⇒ ⊢ (𝜑 → 𝜃) | ||
| Theorem | mp3an1i 1371 | An inference based on modus ponens. (Contributed by NM, 5-Jul-2005.) |
| ⊢ 𝜓 & ⊢ (𝜑 → ((𝜓 ∧ 𝜒 ∧ 𝜃) → 𝜏)) ⇒ ⊢ (𝜑 → ((𝜒 ∧ 𝜃) → 𝜏)) | ||
| Theorem | mp3anl1 1372 | An inference based on modus ponens. (Contributed by NM, 24-Feb-2005.) |
| ⊢ 𝜑 & ⊢ (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃) → 𝜏) ⇒ ⊢ (((𝜓 ∧ 𝜒) ∧ 𝜃) → 𝜏) | ||
| Theorem | mp3anl2 1373 | An inference based on modus ponens. (Contributed by NM, 24-Feb-2005.) |
| ⊢ 𝜓 & ⊢ (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃) → 𝜏) ⇒ ⊢ (((𝜑 ∧ 𝜒) ∧ 𝜃) → 𝜏) | ||
| Theorem | mp3anl3 1374 | An inference based on modus ponens. (Contributed by NM, 24-Feb-2005.) |
| ⊢ 𝜒 & ⊢ (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃) → 𝜏) ⇒ ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜃) → 𝜏) | ||
| Theorem | mp3anr1 1375 | An inference based on modus ponens. (Contributed by NM, 4-Nov-2006.) |
| ⊢ 𝜓 & ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒 ∧ 𝜃)) → 𝜏) ⇒ ⊢ ((𝜑 ∧ (𝜒 ∧ 𝜃)) → 𝜏) | ||
| Theorem | mp3anr2 1376 | An inference based on modus ponens. (Contributed by NM, 24-Nov-2006.) |
| ⊢ 𝜒 & ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒 ∧ 𝜃)) → 𝜏) ⇒ ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜃)) → 𝜏) | ||
| Theorem | mp3anr3 1377 | An inference based on modus ponens. (Contributed by NM, 19-Oct-2007.) |
| ⊢ 𝜃 & ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒 ∧ 𝜃)) → 𝜏) ⇒ ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜏) | ||
| Theorem | mp3an 1378 | An inference based on modus ponens. (Contributed by NM, 14-May-1999.) |
| ⊢ 𝜑 & ⊢ 𝜓 & ⊢ 𝜒 & ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜃) ⇒ ⊢ 𝜃 | ||
| Theorem | mpd3an3 1379 | An inference based on modus ponens. (Contributed by NM, 8-Nov-2007.) |
| ⊢ ((𝜑 ∧ 𝜓) → 𝜒) & ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜃) | ||
| Theorem | mpd3an23 1380 | An inference based on modus ponens. (Contributed by NM, 4-Dec-2006.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜃) ⇒ ⊢ (𝜑 → 𝜃) | ||
| Theorem | mp3and 1381 | A deduction based on modus ponens. (Contributed by Mario Carneiro, 24-Dec-2016.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → 𝜃) & ⊢ (𝜑 → ((𝜓 ∧ 𝜒 ∧ 𝜃) → 𝜏)) ⇒ ⊢ (𝜑 → 𝜏) | ||
| Theorem | mp3an12i 1382 | mp3an 1378 with antecedents in standard conjunction form and with one hypothesis an implication. (Contributed by Alan Sare, 28-Aug-2016.) |
| ⊢ 𝜑 & ⊢ 𝜓 & ⊢ (𝜒 → 𝜃) & ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜃) → 𝜏) ⇒ ⊢ (𝜒 → 𝜏) | ||
| Theorem | mp3an2i 1383 | mp3an 1378 with antecedents in standard conjunction form and with two hypotheses which are implications. (Contributed by Alan Sare, 28-Aug-2016.) |
| ⊢ 𝜑 & ⊢ (𝜓 → 𝜒) & ⊢ (𝜓 → 𝜃) & ⊢ ((𝜑 ∧ 𝜒 ∧ 𝜃) → 𝜏) ⇒ ⊢ (𝜓 → 𝜏) | ||
| Theorem | mp3an3an 1384 | mp3an 1378 with antecedents in standard conjunction form and with two hypotheses which are implications. (Contributed by Alan Sare, 28-Aug-2016.) |
| ⊢ 𝜑 & ⊢ (𝜓 → 𝜒) & ⊢ (𝜃 → 𝜏) & ⊢ ((𝜑 ∧ 𝜒 ∧ 𝜏) → 𝜂) ⇒ ⊢ ((𝜓 ∧ 𝜃) → 𝜂) | ||
| Theorem | mp3an2ani 1385 | An elimination deduction. (Contributed by Alan Sare, 17-Oct-2017.) |
| ⊢ 𝜑 & ⊢ (𝜓 → 𝜒) & ⊢ ((𝜓 ∧ 𝜃) → 𝜏) & ⊢ ((𝜑 ∧ 𝜒 ∧ 𝜏) → 𝜂) ⇒ ⊢ ((𝜓 ∧ 𝜃) → 𝜂) | ||
| Theorem | biimp3a 1386 | Infer implication from a logical equivalence. Similar to biimpa 296. (Contributed by NM, 4-Sep-2005.) |
| ⊢ ((𝜑 ∧ 𝜓) → (𝜒 ↔ 𝜃)) ⇒ ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜃) | ||
| Theorem | biimp3ar 1387 | Infer implication from a logical equivalence. Similar to biimpar 297. (Contributed by NM, 2-Jan-2009.) |
| ⊢ ((𝜑 ∧ 𝜓) → (𝜒 ↔ 𝜃)) ⇒ ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜃) → 𝜒) | ||
| Theorem | 3anandis 1388 | Inference that undistributes a triple conjunction in the antecedent. (Contributed by NM, 18-Apr-2007.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜑 ∧ 𝜒) ∧ (𝜑 ∧ 𝜃)) → 𝜏) ⇒ ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒 ∧ 𝜃)) → 𝜏) | ||
| Theorem | 3anandirs 1389 | Inference that undistributes a triple conjunction in the antecedent. (Contributed by NM, 25-Jul-2006.) (Revised by NM, 18-Apr-2007.) |
| ⊢ (((𝜑 ∧ 𝜃) ∧ (𝜓 ∧ 𝜃) ∧ (𝜒 ∧ 𝜃)) → 𝜏) ⇒ ⊢ (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃) → 𝜏) | ||
| Theorem | ecased 1390 | Deduction form of disjunctive syllogism. (Contributed by Jim Kingdon, 9-Dec-2017.) |
| ⊢ (𝜑 → ¬ 𝜒) & ⊢ (𝜑 → (𝜓 ∨ 𝜒)) ⇒ ⊢ (𝜑 → 𝜓) | ||
| Theorem | ecase23d 1391 | Variation of ecased 1390 with three disjuncts instead of two. (Contributed by NM, 22-Apr-1994.) (Revised by Jim Kingdon, 9-Dec-2017.) |
| ⊢ (𝜑 → ¬ 𝜒) & ⊢ (𝜑 → ¬ 𝜃) & ⊢ (𝜑 → (𝜓 ∨ 𝜒 ∨ 𝜃)) ⇒ ⊢ (𝜑 → 𝜓) | ||
| Theorem | ecase2d 1392 | Deduction for elimination by cases. (Contributed by NM, 21-Apr-1994.) (Proof shortened by Wolf Lammen, 19-Sep-2024.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) & ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜃)) & ⊢ (𝜑 → (𝜏 ∨ (𝜒 ∨ 𝜃))) ⇒ ⊢ (𝜑 → 𝜏) | ||
| Theorem | 3bior1fd 1393 | A disjunction is equivalent to a threefold disjunction with single falsehood, analogous to biorf 756. (Contributed by Alexander van der Vekens, 8-Sep-2017.) |
| ⊢ (𝜑 → ¬ 𝜃) ⇒ ⊢ (𝜑 → ((𝜒 ∨ 𝜓) ↔ (𝜃 ∨ 𝜒 ∨ 𝜓))) | ||
| Theorem | 3bior1fand 1394 | A disjunction is equivalent to a threefold disjunction with single falsehood of a conjunction. (Contributed by Alexander van der Vekens, 8-Sep-2017.) |
| ⊢ (𝜑 → ¬ 𝜃) ⇒ ⊢ (𝜑 → ((𝜒 ∨ 𝜓) ↔ ((𝜃 ∧ 𝜏) ∨ 𝜒 ∨ 𝜓))) | ||
| Theorem | 3bior2fd 1395 | A wff is equivalent to its threefold disjunction with double falsehood, analogous to biorf 756. (Contributed by Alexander van der Vekens, 8-Sep-2017.) |
| ⊢ (𝜑 → ¬ 𝜃) & ⊢ (𝜑 → ¬ 𝜒) ⇒ ⊢ (𝜑 → (𝜓 ↔ (𝜃 ∨ 𝜒 ∨ 𝜓))) | ||
| Theorem | 3biant1d 1396 | A conjunction is equivalent to a threefold conjunction with single truth, analogous to biantrud 304. (Contributed by Alexander van der Vekens, 26-Sep-2017.) |
| ⊢ (𝜑 → 𝜃) ⇒ ⊢ (𝜑 → ((𝜒 ∧ 𝜓) ↔ (𝜃 ∧ 𝜒 ∧ 𝜓))) | ||
| Theorem | intn3an1d 1397 | Introduction of a triple conjunct inside a contradiction. (Contributed by FL, 27-Dec-2007.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
| ⊢ (𝜑 → ¬ 𝜓) ⇒ ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒 ∧ 𝜃)) | ||
| Theorem | intn3an2d 1398 | Introduction of a triple conjunct inside a contradiction. (Contributed by FL, 27-Dec-2007.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
| ⊢ (𝜑 → ¬ 𝜓) ⇒ ⊢ (𝜑 → ¬ (𝜒 ∧ 𝜓 ∧ 𝜃)) | ||
| Theorem | intn3an3d 1399 | Introduction of a triple conjunct inside a contradiction. (Contributed by FL, 27-Dec-2007.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
| ⊢ (𝜑 → ¬ 𝜓) ⇒ ⊢ (𝜑 → ¬ (𝜒 ∧ 𝜃 ∧ 𝜓)) | ||
Even though it is not ordinarily part of propositional calculus, the universal quantifier ∀ is introduced here so that the soundness of Definition df-tru 1405 can be checked by the same algorithm that is used for predicate calculus. Its first real use is in Axiom ax-5 1500 in the predicate calculus section below. For those who want propositional calculus to be self-contained, i.e., to use wff variables only, the alternate Definition dftru2 1410 may be adopted and this subsection moved down to the start of the subsection with wex 1545 below. However, the use of dftru2 1410 as a definition requires a more elaborate definition checking algorithm that we prefer to avoid. | ||
| Syntax | wal 1400 | Extend wff definition to include the universal quantifier ("for all"). ∀𝑥𝜑 is read "𝜑 (phi) is true for all 𝑥". Typically, in its final application 𝜑 would be replaced with a wff containing a (free) occurrence of the variable 𝑥, for example 𝑥 = 𝑦. In a universe with a finite number of objects, "for all" is equivalent to a big conjunction (AND) with one wff for each possible case of 𝑥. When the universe is infinite (as with set theory), such a propositional-calculus equivalent is not possible because an infinitely long formula has no meaning, but conceptually the idea is the same. |
| wff ∀𝑥𝜑 | ||
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