Theorem 3jaod 1341

Description: Disjunction of 3 antecedents (deduction). (Contributed by NM, 14-Oct-2005.)

Hypotheses

Ref	Expression
3jaod.1	⊢ (𝜑 → (𝜓 → 𝜒))
3jaod.2	⊢ (𝜑 → (𝜃 → 𝜒))
3jaod.3	⊢ (𝜑 → (𝜏 → 𝜒))

Assertion

Ref	Expression
3jaod	⊢ (𝜑 → ((𝜓 ∨ 𝜃 ∨ 𝜏) → 𝜒))

Proof of Theorem 3jaod

Step	Hyp	Ref	Expression
1		3jaod.1	. 2 ⊢ (𝜑 → (𝜓 → 𝜒))
2		3jaod.2	. 2 ⊢ (𝜑 → (𝜃 → 𝜒))
3		3jaod.3	. 2 ⊢ (𝜑 → (𝜏 → 𝜒))
4		3jao 1338	. 2 ⊢ (((𝜓 → 𝜒) ∧ (𝜃 → 𝜒) ∧ (𝜏 → 𝜒)) → ((𝜓 ∨ 𝜃 ∨ 𝜏) → 𝜒))
5	1, 2, 3, 4	syl3anc 1274	1 ⊢ (𝜑 → ((𝜓 ∨ 𝜃 ∨ 𝜏) → 𝜒))

Syntax hints:   → wi 4   ∨ w3o 1004

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 717

This theorem depends on definitions:  df-bi 117  df-3or 1006  df-3an 1007

This theorem is referenced by:  3jaodan  1343  3jaao  1345  issod  4445  nnawordex  6775  exmidontri2or  7566  addlocprlem  7866  nqprloc  7876  ltexprlemrl  7941  aptiprleml  7970  aptiprlemu  7971  elnn0z  9607  zaddcl  9634  zletric  9638  zlelttric  9639  zltnle  9640  zdceq  9670  zdcle  9671  zdclt  9672  nn01to3  9967  xposdif  10234  fzdcel  10394  qletric  10625  qlelttric  10626  qltnle  10627  qdceq  10628  qdclt  10629  frec2uzlt2d  10790  perfectlem2  15994  triap  16939  tridceq  16967