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Theorem dfom3 4690
Description: Alias for df-iom 4689. Use it instead of df-iom 4689 for naming consistency with set.mm. (Contributed by NM, 6-Aug-1994.)
Assertion
Ref Expression
dfom3 ω = {𝑥 ∣ (∅ ∈ 𝑥 ∧ ∀𝑦𝑥 suc 𝑦𝑥)}
Distinct variable group:   𝑥,𝑦

Proof of Theorem dfom3
StepHypRef Expression
1 df-iom 4689 1 ω = {𝑥 ∣ (∅ ∈ 𝑥 ∧ ∀𝑦𝑥 suc 𝑦𝑥)}
Colors of variables: wff set class
Syntax hints:  wa 104   = wceq 1397  wcel 2202  {cab 2217  wral 2510  c0 3494   cint 3928  suc csuc 4462  ωcom 4688
This theorem depends on definitions:  df-iom 4689
This theorem is referenced by:  omex  4691  peano1  4692  peano2  4693  peano5  4696  bj-dfom  16528
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