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Theorem bj-dfom 13120
Description: Alternate definition of ω, as the intersection of all the inductive sets. Proposal: make this the definition. (Contributed by BJ, 30-Nov-2019.)
Assertion
Ref Expression
bj-dfom ω = {𝑥 ∣ Ind 𝑥}

Proof of Theorem bj-dfom
Dummy variable 𝑦 is distinct from all other variables.
StepHypRef Expression
1 dfom3 4501 . 2 ω = {𝑥 ∣ (∅ ∈ 𝑥 ∧ ∀𝑦𝑥 suc 𝑦𝑥)}
2 df-bj-ind 13114 . . . . 5 (Ind 𝑥 ↔ (∅ ∈ 𝑥 ∧ ∀𝑦𝑥 suc 𝑦𝑥))
32bicomi 131 . . . 4 ((∅ ∈ 𝑥 ∧ ∀𝑦𝑥 suc 𝑦𝑥) ↔ Ind 𝑥)
43abbii 2253 . . 3 {𝑥 ∣ (∅ ∈ 𝑥 ∧ ∀𝑦𝑥 suc 𝑦𝑥)} = {𝑥 ∣ Ind 𝑥}
54inteqi 3770 . 2 {𝑥 ∣ (∅ ∈ 𝑥 ∧ ∀𝑦𝑥 suc 𝑦𝑥)} = {𝑥 ∣ Ind 𝑥}
61, 5eqtri 2158 1 ω = {𝑥 ∣ Ind 𝑥}
Colors of variables: wff set class
Syntax hints:  wa 103   = wceq 1331  wcel 1480  {cab 2123  wral 2414  c0 3358   cint 3766  suc csuc 4282  ωcom 4499  Ind wind 13113
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-io 698  ax-5 1423  ax-7 1424  ax-gen 1425  ax-ie1 1469  ax-ie2 1470  ax-8 1482  ax-10 1483  ax-11 1484  ax-i12 1485  ax-bndl 1486  ax-4 1487  ax-17 1506  ax-i9 1510  ax-ial 1514  ax-i5r 1515  ax-ext 2119
This theorem depends on definitions:  df-bi 116  df-tru 1334  df-nf 1437  df-sb 1736  df-clab 2124  df-cleq 2130  df-clel 2133  df-nfc 2268  df-ral 2419  df-int 3767  df-iom 4500  df-bj-ind 13114
This theorem is referenced by:  bj-omind  13121  bj-omssind  13122  bj-ssom  13123
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