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Mirrors > Home > ILE Home > Th. List > ibd | GIF version |
Description: Deduction that converts a biconditional implied by one of its arguments, into an implication. (Contributed by NM, 26-Jun-2004.) |
Ref | Expression |
---|---|
ibd.1 | ⊢ (𝜑 → (𝜓 → (𝜓 ↔ 𝜒))) |
Ref | Expression |
---|---|
ibd | ⊢ (𝜑 → (𝜓 → 𝜒)) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | ibd.1 | . 2 ⊢ (𝜑 → (𝜓 → (𝜓 ↔ 𝜒))) | |
2 | biimp 117 | . 2 ⊢ ((𝜓 ↔ 𝜒) → (𝜓 → 𝜒)) | |
3 | 1, 2 | syli 37 | 1 ⊢ (𝜑 → (𝜓 → 𝜒)) |
Colors of variables: wff set class |
Syntax hints: → wi 4 ↔ wb 104 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 105 |
This theorem depends on definitions: df-bi 116 |
This theorem is referenced by: pm5.21ndd 695 oibabs 704 sssnm 3734 |
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