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Theorem or42 784
Description: Rearrangement of 4 disjuncts. (Contributed by NM, 10-Jan-2005.)
Assertion
Ref Expression
or42 (((𝜑 ∨ 𝜓) ∨ (𝜒 ∨ 𝜃)) ↔ ((𝜑 ∨ 𝜒) ∨ (𝜃 ∨ 𝜓)))

Proof of Theorem or42
StepHypRef Expression
1 or4 783 . 2 (((𝜑 ∨ 𝜓) ∨ (𝜒 ∨ 𝜃)) ↔ ((𝜑 ∨ 𝜒) ∨ (𝜓 ∨ 𝜃)))
2 orcom 740 . . 3 ((𝜓 ∨ 𝜃) ↔ (𝜃 ∨ 𝜓))
32orbi2i 774 . 2 (((𝜑 ∨ 𝜒) ∨ (𝜓 ∨ 𝜃)) ↔ ((𝜑 ∨ 𝜒) ∨ (𝜃 ∨ 𝜓)))
41, 3bitri 184 1 (((𝜑 ∨ 𝜓) ∨ (𝜒 ∨ 𝜃)) ↔ ((𝜑 ∨ 𝜒) ∨ (𝜃 ∨ 𝜓)))
Colors of variables:    wff set class
This proof depends on syntax axioms:   ↔ wb 105   ∨ wo 720
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 721
This proof depends on definitions:  df-bi 117
This theorem is used by:  reapcotr  8929
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