| Mathbox for Jarvin Udandy |
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| Mirrors > Home > MPE Home > Th. List > Mathboxes > atbiffatnnb | Structured version Visualization version GIF version | ||
| Description: If a implies b, then a implies not not b. (Contributed by Jarvin Udandy, 28-Aug-2016.) |
| Ref | Expression |
|---|---|
| atbiffatnnb | ⊢ ((𝜑 → 𝜓) → (𝜑 → ¬ ¬ 𝜓)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | idd 24 | . . 3 ⊢ (𝜑 → (𝜓 → 𝜓)) | |
| 2 | notnotb 315 | . . 3 ⊢ (𝜓 ↔ ¬ ¬ 𝜓) | |
| 3 | 1, 2 | imbitrdi 251 | . 2 ⊢ (𝜑 → (𝜓 → ¬ ¬ 𝜓)) |
| 4 | 3 | a2i 14 | 1 ⊢ ((𝜑 → 𝜓) → (𝜑 → ¬ ¬ 𝜓)) |
| Colors of variables: wff setvar class |
| Syntax hints: ¬ wn 3 → wi 4 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 |
| This theorem depends on definitions: df-bi 207 |
| This theorem is referenced by: atbiffatnnbalt 46872 |
| Copyright terms: Public domain | W3C validator |