Theorem frege53c 44754

Description: Proposition 53 of [Frege1879] p. 50. (Contributed by RP, 24-Dec-2019.) (Proof modification is discouraged.)

Assertion

Ref	Expression
frege53c	⊢ ([𝐴 / 𝑥]𝜑 → (𝐴 = 𝐵 → [𝐵 / 𝑥]𝜑))

Proof of Theorem frege53c

Step	Hyp	Ref	Expression
1		ax-frege52c 44728	. 2 ⊢ (𝐴 = 𝐵 → ([𝐴 / 𝑥]𝜑 → [𝐵 / 𝑥]𝜑))
2		ax-frege8 44649	. 2 ⊢ ((𝐴 = 𝐵 → ([𝐴 / 𝑥]𝜑 → [𝐵 / 𝑥]𝜑)) → ([𝐴 / 𝑥]𝜑 → (𝐴 = 𝐵 → [𝐵 / 𝑥]𝜑)))
3	1, 2	ax-mp 5	1 ⊢ ([𝐴 / 𝑥]𝜑 → (𝐴 = 𝐵 → [𝐵 / 𝑥]𝜑))

This proof depends on syntax axioms:   → wi 4   = wceq 1570  [wsbc 3739

This proof depends on axioms:  ax-mp 5  ax-frege8 44649  ax-frege52c 44728

This theorem is used by:  frege55lem2c  44757  frege55c  44758  frege56c  44759  frege92  44795