Theorem hbaltg 36305

Description: A more general and closed form of hbal 2201. (Contributed by Scott Fenton, 13-Dec-2010.)

Assertion

Ref	Expression
hbaltg	⊢ (∀𝑥(𝜑 → ∀𝑦𝜓) → (∀𝑥𝜑 → ∀𝑦∀𝑥𝜓))

Proof of Theorem hbaltg

Step	Hyp	Ref	Expression
1		alim 1839	. 2 ⊢ (∀𝑥(𝜑 → ∀𝑦𝜓) → (∀𝑥𝜑 → ∀𝑥∀𝑦𝜓))
2		ax-11 2191	. 2 ⊢ (∀𝑥∀𝑦𝜓 → ∀𝑦∀𝑥𝜓)
3	1, 2	syl6 36	1 ⊢ (∀𝑥(𝜑 → ∀𝑦𝜓) → (∀𝑥𝜑 → ∀𝑦∀𝑥𝜓))

This proof depends on syntax axioms:   → wi 4  ∀wal 1567

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-4 1838  ax-11 2191

This theorem is used by: (None)