Theorem hbimtg 36660

Description: A more general and closed form of hbim 2332. (Contributed by Scott Fenton, 13-Dec-2010.)

Assertion

Ref	Expression
hbimtg	⊢ ((∀𝑥(𝜑 → ∀𝑥𝜒) ∧ (𝜓 → ∀𝑥𝜃)) → ((𝜒 → 𝜓) → ∀𝑥(𝜑 → 𝜃)))

Proof of Theorem hbimtg

Step	Hyp	Ref	Expression
1		hbntg 36659	. . . 4 ⊢ (∀𝑥(𝜑 → ∀𝑥𝜒) → (¬ 𝜒 → ∀𝑥 ¬ 𝜑))
2		pm2.21 124	. . . . 5 ⊢ (¬ 𝜑 → (𝜑 → 𝜃))
3	2	alimi 1843	. . . 4 ⊢ (∀𝑥 ¬ 𝜑 → ∀𝑥(𝜑 → 𝜃))
4	1, 3	syl6 36	. . 3 ⊢ (∀𝑥(𝜑 → ∀𝑥𝜒) → (¬ 𝜒 → ∀𝑥(𝜑 → 𝜃)))
5	4	adantr 486	. 2 ⊢ ((∀𝑥(𝜑 → ∀𝑥𝜒) ∧ (𝜓 → ∀𝑥𝜃)) → (¬ 𝜒 → ∀𝑥(𝜑 → 𝜃)))
6		ala1 1845	. . . 4 ⊢ (∀𝑥𝜃 → ∀𝑥(𝜑 → 𝜃))
7	6	imim2i 17	. . 3 ⊢ ((𝜓 → ∀𝑥𝜃) → (𝜓 → ∀𝑥(𝜑 → 𝜃)))
8	7	adantl 487	. 2 ⊢ ((∀𝑥(𝜑 → ∀𝑥𝜒) ∧ (𝜓 → ∀𝑥𝜃)) → (𝜓 → ∀𝑥(𝜑 → 𝜃)))
9	5, 8	jad 189	1 ⊢ ((∀𝑥(𝜑 → ∀𝑥𝜒) ∧ (𝜓 → ∀𝑥𝜃)) → ((𝜒 → 𝜓) → ∀𝑥(𝜑 → 𝜃)))

This proof depends on syntax axioms:  ¬ wn 3   → wi 4   ∧ wa 401  ∀wal 1567

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-10 2177  ax-12 2212

This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1812

This theorem is used by:  hbimg  36663