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Theorem hbimtg 36229
Description: A more general and closed form of hbim 2340. (Contributed by Scott Fenton, 13-Dec-2010.)
Assertion
Ref Expression
hbimtg ((∀𝑥(𝜑 → ∀𝑥𝜒) ∧ (𝜓 → ∀𝑥𝜃)) → ((𝜒𝜓) → ∀𝑥(𝜑𝜃)))

Proof of Theorem hbimtg
StepHypRef Expression
1 hbntg 36228 . . . 4 (∀𝑥(𝜑 → ∀𝑥𝜒) → (¬ 𝜒 → ∀𝑥 ¬ 𝜑))
2 pm2.21 124 . . . . 5 𝜑 → (𝜑𝜃))
32alimi 1838 . . . 4 (∀𝑥 ¬ 𝜑 → ∀𝑥(𝜑𝜃))
41, 3syl6 36 . . 3 (∀𝑥(𝜑 → ∀𝑥𝜒) → (¬ 𝜒 → ∀𝑥(𝜑𝜃)))
54adantr 485 . 2 ((∀𝑥(𝜑 → ∀𝑥𝜒) ∧ (𝜓 → ∀𝑥𝜃)) → (¬ 𝜒 → ∀𝑥(𝜑𝜃)))
6 ala1 1840 . . . 4 (∀𝑥𝜃 → ∀𝑥(𝜑𝜃))
76imim2i 17 . . 3 ((𝜓 → ∀𝑥𝜃) → (𝜓 → ∀𝑥(𝜑𝜃)))
87adantl 486 . 2 ((∀𝑥(𝜑 → ∀𝑥𝜒) ∧ (𝜓 → ∀𝑥𝜃)) → (𝜓 → ∀𝑥(𝜑𝜃)))
95, 8jad 189 1 ((∀𝑥(𝜑 → ∀𝑥𝜒) ∧ (𝜓 → ∀𝑥𝜃)) → ((𝜒𝜓) → ∀𝑥(𝜑𝜃)))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wi 4  wa 400  wal 1565
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1822  ax-4 1836  ax-5 1937  ax-6 1994  ax-7 2035  ax-10 2182  ax-12 2219
This theorem depends on definitions:  df-bi 210  df-an 401  df-ex 1807
This theorem is referenced by:  hbimg  36232
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