Theorem orimdi 929

Description: Disjunction distributes over implication. (Contributed by Wolf Lammen, 5-Jan-2013.)

Assertion

Ref	Expression
orimdi	⊢ ((𝜑 ∨ (𝜓 → 𝜒)) ↔ ((𝜑 ∨ 𝜓) → (𝜑 ∨ 𝜒)))

Proof of Theorem orimdi

Step	Hyp	Ref	Expression
1		imdi 389	. 2 ⊢ ((¬ 𝜑 → (𝜓 → 𝜒)) ↔ ((¬ 𝜑 → 𝜓) → (¬ 𝜑 → 𝜒)))
2		df-or 847	. 2 ⊢ ((𝜑 ∨ (𝜓 → 𝜒)) ↔ (¬ 𝜑 → (𝜓 → 𝜒)))
3		df-or 847	. . 3 ⊢ ((𝜑 ∨ 𝜓) ↔ (¬ 𝜑 → 𝜓))
4		df-or 847	. . 3 ⊢ ((𝜑 ∨ 𝜒) ↔ (¬ 𝜑 → 𝜒))
5	3, 4	imbi12i 350	. 2 ⊢ (((𝜑 ∨ 𝜓) → (𝜑 ∨ 𝜒)) ↔ ((¬ 𝜑 → 𝜓) → (¬ 𝜑 → 𝜒)))
6	1, 2, 5	3bitr4i 303	1 ⊢ ((𝜑 ∨ (𝜓 → 𝜒)) ↔ ((𝜑 ∨ 𝜓) → (𝜑 ∨ 𝜒)))

Syntax hints:  ¬ wn 3   → wi 4   ↔ wb 205   ∨ wo 846

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 206  df-or 847

This theorem is referenced by:  pm2.76  930  pm2.85  931