Theorem r19.2zb 3641

Description: A response to the notion that the condition A =/= (/) can be removed in r19.2z 3640. Interestingly enough, ph does not figure in the left-hand side. (Contributed by Jeff Hankins, 24-Aug-2009.)

Assertion

Ref	Expression
r19.2zb	|- (A =/= (/) <-> (A.x e. A ph -> E.x e. A ph))

Distinct variable group:   x,A

Allowed substitution hint:   ph(x)

Proof of Theorem r19.2zb

Step	Hyp	Ref	Expression
1		r19.2z 3640	. . 3 |- ((A =/= (/) /\ A.x e. A ph) -> E.x e. A ph)
2	1	ex 423	. 2 |- (A =/= (/) -> (A.x e. A ph -> E.x e. A ph))
3		noel 3555	. . . . . . 7 |- -. x e. (/)
4	3	pm2.21i 123	. . . . . 6 |- (x e. (/) -> ph)
5	4	rgen 2680	. . . . 5 |- A.x e. (/) ph
6		raleq 2808	. . . . 5 |- (A = (/) -> (A.x e. A ph <-> A.x e. (/) ph))
7	5, 6	mpbiri 224	. . . 4 |- (A = (/) -> A.x e. A ph)
8	7	necon3bi 2558	. . 3 |- (-. A.x e. A ph -> A =/= (/))
9		exsimpl 1592	. . . 4 |- (E.x(x e. A /\ ph) -> E.x x e. A)
10		df-rex 2621	. . . 4 |- (E.x e. A ph <-> E.x(x e. A /\ ph))
11		n0 3560	. . . 4 |- (A =/= (/) <-> E.x x e. A)
12	9, 10, 11	3imtr4i 257	. . 3 |- (E.x e. A ph -> A =/= (/))
13	8, 12	ja 153	. 2 |- ((A.x e. A ph -> E.x e. A ph) -> A =/= (/))
14	2, 13	impbii 180	1 |- (A =/= (/) <-> (A.x e. A ph -> E.x e. A ph))

Syntax hints:   -> wi 4   <-> wb 176   /\ wa 358  E.wex 1541   = wceq 1642   e. wcel 1710   =/= wne 2517  A.wral 2615  E.wrex 2616  (/)c0 3551

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334

This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-nan 1288  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2340  df-cleq 2346  df-clel 2349  df-nfc 2479  df-ne 2519  df-ral 2620  df-rex 2621  df-v 2862  df-nin 3212  df-compl 3213  df-in 3214  df-dif 3216  df-nul 3552

This theorem is referenced by: (None)