Theorem sbralie 2848

Description: Implicit to explicit substitution that swaps variables in a quantified expression. (Contributed by NM, 5-Sep-2004.)

Hypothesis

Ref	Expression
sbralie.1	|- (x = y -> (ph <-> ps))

Assertion

Ref	Expression
sbralie	|- (A.x e. y ph <-> [y / x]A.y e. x ps)

Distinct variable groups:   x,y   ps,x   ph,y

Allowed substitution hints:   ph(x)   ps(y)

Proof of Theorem sbralie

Dummy variable z is distinct from all other variables.

Step	Hyp	Ref	Expression
1		cbvralsv 2846	. . 3 |- (A.y e. x ps <-> A.z e. x [z / y]ps)
2	1	sbbii 1653	. 2 |- ([y / x]A.y e. x ps <-> [y / x]A.z e. x [z / y]ps)
3		nfv 1619	. . 3 |- F/xA.z e. y [z / y]ps
4		raleq 2807	. . 3 |- (x = y -> (A.z e. x [z / y]ps <-> A.z e. y [z / y]ps))
5	3, 4	sbie 2038	. 2 |- ([y / x]A.z e. x [z / y]ps <-> A.z e. y [z / y]ps)
6		cbvralsv 2846	. . 3 |- (A.z e. y [z / y]ps <-> A.x e. y [x / z][z / y]ps)
7		nfv 1619	. . . . . 6 |- F/zps
8	7	sbco2 2086	. . . . 5 |- ([x / z][z / y]ps <-> [x / y]ps)
9		nfv 1619	. . . . . 6 |- F/yph
10		sbralie.1	. . . . . . . 8 |- (x = y -> (ph <-> ps))
11	10	bicomd 192	. . . . . . 7 |- (x = y -> (ps <-> ph))
12	11	equcoms 1681	. . . . . 6 |- (y = x -> (ps <-> ph))
13	9, 12	sbie 2038	. . . . 5 |- ([x / y]ps <-> ph)
14	8, 13	bitri 240	. . . 4 |- ([x / z][z / y]ps <-> ph)
15	14	ralbii 2638	. . 3 |- (A.x e. y [x / z][z / y]ps <-> A.x e. y ph)
16	6, 15	bitri 240	. 2 |- (A.z e. y [z / y]ps <-> A.x e. y ph)
17	2, 5, 16	3bitrri 263	1 |- (A.x e. y ph <-> [y / x]A.y e. x ps)

Syntax hints:   -> wi 4   <-> wb 176  [wsb 1648  A.wral 2614

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334

This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-cleq 2346  df-clel 2349  df-nfc 2478  df-ral 2619

This theorem is referenced by: (None)