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Theorem equid1 2158
Description: Identity law for equality (reflexivity). Lemma 6 of [Tarski] p. 68. This is often an axiom of equality in textbook systems, but we don't need it as an axiom since it can be proved from our other axioms (although the proof, as you can see below, is not as obvious as you might think). This proof uses only axioms without distinct variable conditions and thus requires no dummy variables. A simpler proof, similar to Tarki's, is possible if we make use of ax-17 1616; see the proof of equid 1676. See equid1ALT 2176 for an alternate proof. (Contributed by NM, 5-Aug-1993.) (Proof modification is discouraged.) (New usage is discouraged.)
Assertion
Ref Expression
equid1 x = x

Proof of Theorem equid1
StepHypRef Expression
1 ax-5o 2136 . . . 4 (x(x ¬ x x = x → (x = xx x = x)) → (x ¬ x x = xx(x = xx x = x)))
2 ax-4 2135 . . . . 5 (x ¬ x x = x → ¬ x x = x)
3 ax-12o 2142 . . . . 5 x x = x → (¬ x x = x → (x = xx x = x)))
42, 2, 3sylc 56 . . . 4 (x ¬ x x = x → (x = xx x = x))
51, 4mpg 1548 . . 3 (x ¬ x x = xx(x = xx x = x))
6 ax-9o 2138 . . 3 (x(x = xx x = x) → x = x)
75, 6syl 15 . 2 (x ¬ x x = xx = x)
8 ax-6o 2137 . 2 x ¬ x x = xx = x)
97, 8pm2.61i 156 1 x = x
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wi 4  wal 1540
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-4 2135  ax-5o 2136  ax-6o 2137  ax-9o 2138  ax-12o 2142
This theorem is referenced by: (None)
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