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Theorem orddi 839
Description: Double distributive law for disjunction. (Contributed by NM, 12-Aug-1994.)
Assertion
Ref Expression
orddi ⊢ (((φ ∧ ψ) ∨ (χ ∧ θ)) ↔ (((φ ∨ χ) ∧ (φ ∨ θ)) ∧ ((ψ ∨ χ) ∧ (ψ ∨ θ))))

Proof of Theorem orddi
StepHypRef Expression
1 ordir 835 . 2 ⊢ (((φ ∧ ψ) ∨ (χ ∧ θ)) ↔ ((φ ∨ (χ ∧ θ)) ∧ (ψ ∨ (χ ∧ θ))))
2 ordi 834 . . 3 ⊢ ((φ ∨ (χ ∧ θ)) ↔ ((φ ∨ χ) ∧ (φ ∨ θ)))
3 ordi 834 . . 3 ⊢ ((ψ ∨ (χ ∧ θ)) ↔ ((ψ ∨ χ) ∧ (ψ ∨ θ)))
42, 3anbi12i 678 . 2 ⊢ (((φ ∨ (χ ∧ θ)) ∧ (ψ ∨ (χ ∧ θ))) ↔ (((φ ∨ χ) ∧ (φ ∨ θ)) ∧ ((ψ ∨ χ) ∧ (ψ ∨ θ))))
51, 4bitri 240 1 ⊢ (((φ ∧ ψ) ∨ (χ ∧ θ)) ↔ (((φ ∨ χ) ∧ (φ ∨ θ)) ∧ ((ψ ∨ χ) ∧ (ψ ∨ θ))))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ↔ wb 176   ∨ wo 357   ∧ wa 358
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 177  df-or 359  df-an 360
This theorem is used by: (None)
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