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Mirrors > Home > QLE Home > Th. List > u1lem1 | GIF version |
Description: Lemma for unified implication study. (Contributed by NM, 14-Dec-1997.) |
Ref | Expression |
---|---|
u1lem1 | ((a →1 b) →1 a) = a |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | u1lemc1 680 | . . . 4 a C (a →1 b) | |
2 | 1 | comcom 453 | . . 3 (a →1 b) C a |
3 | 2 | u1lemc4 701 | . 2 ((a →1 b) →1 a) = ((a →1 b)⊥ ∪ a) |
4 | u1lemnoa 660 | . 2 ((a →1 b)⊥ ∪ a) = a | |
5 | 3, 4 | ax-r2 36 | 1 ((a →1 b) →1 a) = a |
Colors of variables: term |
Syntax hints: = wb 1 ⊥ wn 4 ∪ wo 6 →1 wi1 12 |
This theorem was proved from axioms: ax-a1 30 ax-a2 31 ax-a3 32 ax-a4 33 ax-a5 34 ax-r1 35 ax-r2 36 ax-r4 37 ax-r5 38 ax-r3 439 |
This theorem depends on definitions: df-b 39 df-a 40 df-t 41 df-f 42 df-i1 44 df-le1 130 df-le2 131 df-c1 132 df-c2 133 |
This theorem is referenced by: u1lem1n 739 u1lem2 744 |
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