Theorem syld3an1 1406

Description: A syllogism inference. (Contributed by NM, 7-Jul-2008.) (Proof shortened by Wolf Lammen, 26-Jun-2022.)

Hypotheses

Ref	Expression
syld3an1.1	⊢ ((𝜒 ∧ 𝜓 ∧ 𝜃) → 𝜑)
syld3an1.2	⊢ ((𝜑 ∧ 𝜓 ∧ 𝜃) → 𝜏)

Assertion

Ref	Expression
syld3an1	⊢ ((𝜒 ∧ 𝜓 ∧ 𝜃) → 𝜏)

Proof of Theorem syld3an1

Step	Hyp	Ref	Expression
1		syld3an1.1	. 2 ⊢ ((𝜒 ∧ 𝜓 ∧ 𝜃) → 𝜑)
2		simp2 1133	. 2 ⊢ ((𝜒 ∧ 𝜓 ∧ 𝜃) → 𝜓)
3		simp3 1134	. 2 ⊢ ((𝜒 ∧ 𝜓 ∧ 𝜃) → 𝜃)
4		syld3an1.2	. 2 ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜃) → 𝜏)
5	1, 2, 3, 4	syl3anc 1367	1 ⊢ ((𝜒 ∧ 𝜓 ∧ 𝜃) → 𝜏)

Syntax hints:   → wi 4   ∧ w3a 1083

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 209  df-an 399  df-3an 1085

This theorem is referenced by:  npncan  10909  nnpcan  10911  ppncan  10930  muldivdir  11335  subdivcomb1  11337  div2neg  11365  ltmuldiv  11515  opfi1uzind  13862  sgrp2nmndlem4  18095  zndvds  20698  wsuceq123  33103  atlrelat1  36459  cvlatcvr1  36479  dih11  38403  wessf1ornlem  41452  mullimc  41904  mullimcf  41911  icccncfext  42177  stoweidlem34  42326  stoweidlem49  42341  stoweidlem57  42349  sigarexp  43123  el0ldepsnzr  44529