Theorem 3impexpbicomi 1450

Description: Deduction form of 3impexpbicom 1449. (Contributed by Alan Sare, 31-Dec-2011.)

Hypothesis

Ref	Expression
3impexpbicomi.1	|- ( ( ph /\ ps /\ ch ) -> ( th <-> ta ) )

Assertion

Ref	Expression
3impexpbicomi	|- ( ph -> ( ps -> ( ch -> ( ta <-> th ) ) ) )

Proof of Theorem 3impexpbicomi

Step	Hyp	Ref	Expression
1		3impexpbicomi.1	. . 3 |- ( ( ph /\ ps /\ ch ) -> ( th <-> ta ) )
2	1	bicomd 141	. 2 |- ( ( ph /\ ps /\ ch ) -> ( ta <-> th ) )
3	2	3exp 1204	1 |- ( ph -> ( ps -> ( ch -> ( ta <-> th ) ) ) )

Syntax hints:   -> wi 4   <-> wb 105   /\ w3a 980

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108

This theorem depends on definitions:  df-bi 117  df-3an 982

This theorem is referenced by: (None)