Theorem 3netr3g 2401

Description: Substitution of equality into both sides of an inequality. (Contributed by NM, 24-Jul-2012.)

Hypotheses

Ref	Expression
3netr3g.1	⊢ (𝜑 → 𝐴 ≠ 𝐵)
3netr3g.2	⊢ 𝐴 = 𝐶
3netr3g.3	⊢ 𝐵 = 𝐷

Assertion

Ref	Expression
3netr3g	⊢ (𝜑 → 𝐶 ≠ 𝐷)

Proof of Theorem 3netr3g

Step	Hyp	Ref	Expression
1		3netr3g.1	. 2 ⊢ (𝜑 → 𝐴 ≠ 𝐵)
2		3netr3g.2	. . 3 ⊢ 𝐴 = 𝐶
3		3netr3g.3	. . 3 ⊢ 𝐵 = 𝐷
4	2, 3	neeq12i 2384	. 2 ⊢ (𝐴 ≠ 𝐵 ↔ 𝐶 ≠ 𝐷)
5	1, 4	sylib 122	1 ⊢ (𝜑 → 𝐶 ≠ 𝐷)

Syntax hints:   → wi 4   = wceq 1364   ≠ wne 2367

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 615  ax-in2 616  ax-5 1461  ax-gen 1463  ax-4 1524  ax-17 1540  ax-ext 2178

This theorem depends on definitions:  df-bi 117  df-cleq 2189  df-ne 2368

This theorem is referenced by: (None)