Theorem 3netr3g 2296

Description: Substitution of equality into both sides of an inequality. (Contributed by NM, 24-Jul-2012.)

Hypotheses

Ref	Expression
3netr3g.1	|- ( ph -> A =/= B )
3netr3g.2	|- A = C
3netr3g.3	|- B = D

Assertion

Ref	Expression
3netr3g	|- ( ph -> C =/= D )

Proof of Theorem 3netr3g

Step	Hyp	Ref	Expression
1		3netr3g.1	. 2 |- ( ph -> A =/= B )
2		3netr3g.2	. . 3 |- A = C
3		3netr3g.3	. . 3 |- B = D
4	2, 3	neeq12i 2279	. 2 |- ( A =/= B <-> C =/= D )
5	1, 4	sylib 121	1 |- ( ph -> C =/= D )

Syntax hints:   -> wi 4   = wceq 1296   =/= wne 2262

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-in1 582  ax-in2 583  ax-5 1388  ax-gen 1390  ax-4 1452  ax-17 1471  ax-ext 2077

This theorem depends on definitions:  df-bi 116  df-cleq 2088  df-ne 2263

This theorem is referenced by: (None)