Theorem 4p1e5 9443

Description: 4 + 1 = 5. (Contributed by Mario Carneiro, 18-Apr-2015.)

Assertion

Ref	Expression
4p1e5	⊢ (4 + 1) = 5

Proof of Theorem 4p1e5

Step	Hyp	Ref	Expression
1		df-5 9368	. 2 ⊢ 5 = (4 + 1)
2	1	eqcomi 2242	1 ⊢ (4 + 1) = 5

This proof depends on syntax axioms:   = wceq 1402  (class class class)co 6085  1c1 8180   + caddc 8182  4c4 9359  5c5 9360

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1500  ax-gen 1502  ax-ext 2220

This proof depends on definitions:  df-bi 117  df-cleq 2231  df-5 9368

This theorem is used by:  8t7e56  9905  9t6e54  9911  2exp16  13237  prmlem2  13254  163prm  13259  317prm  13260  631prm  13261  1259lem1  13262  1259lem2  13263  1259lem3  13264  1259lem4  13265  log2ublem3  16142  log2ublog2  16143  ex-exp  16839  ex-fac  16840