Theorem 4p1e5 8993

Description: 4 + 1 = 5. (Contributed by Mario Carneiro, 18-Apr-2015.)

Assertion

Ref	Expression
4p1e5	|- ( 4 + 1 ) = 5

Proof of Theorem 4p1e5

Step	Hyp	Ref	Expression
1		df-5 8919	. 2 |- 5 = ( 4 + 1 )
2	1	eqcomi 2169	1 |- ( 4 + 1 ) = 5

Syntax hints:   = wceq 1343  (class class class)co 5842   1c1 7754   + caddc 7756   4c4 8910   5c5 8911

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1435  ax-gen 1437  ax-ext 2147

This theorem depends on definitions:  df-bi 116  df-cleq 2158  df-5 8919

This theorem is referenced by:  8t7e56  9441  9t6e54  9447  ex-exp  13608  ex-fac  13609