Theorem 4p1e5 9423

Description: 4 + 1 = 5. (Contributed by Mario Carneiro, 18-Apr-2015.)

Assertion

Ref	Expression
4p1e5	|- ( 4 + 1 ) = 5

Proof of Theorem 4p1e5

Step	Hyp	Ref	Expression
1		df-5 9348	. 2 |- 5 = ( 4 + 1 )
2	1	eqcomi 2242	1 |- ( 4 + 1 ) = 5

Syntax hints:   = wceq 1402  (class class class)co 6078   1c1 8173   + caddc 8175   4c4 9339   5c5 9340

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1500  ax-gen 1502  ax-ext 2220

This theorem depends on definitions:  df-bi 117  df-cleq 2231  df-5 9348

This theorem is referenced by:  8t7e56  9878  9t6e54  9884  2exp16  13197  ex-exp  16658  ex-fac  16659