Theorem 4p1e5 9127

Description: 4 + 1 = 5. (Contributed by Mario Carneiro, 18-Apr-2015.)

Assertion

Ref	Expression
4p1e5	|- ( 4 + 1 ) = 5

Proof of Theorem 4p1e5

Step	Hyp	Ref	Expression
1		df-5 9052	. 2 |- 5 = ( 4 + 1 )
2	1	eqcomi 2200	1 |- ( 4 + 1 ) = 5

Syntax hints:   = wceq 1364  (class class class)co 5922   1c1 7880   + caddc 7882   4c4 9043   5c5 9044

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1461  ax-gen 1463  ax-ext 2178

This theorem depends on definitions:  df-bi 117  df-cleq 2189  df-5 9052

This theorem is referenced by:  8t7e56  9576  9t6e54  9582  2exp16  12606  ex-exp  15373  ex-fac  15374