Theorem 4p1e5 9069

Description: 4 + 1 = 5. (Contributed by Mario Carneiro, 18-Apr-2015.)

Assertion

Ref	Expression
4p1e5	|- ( 4 + 1 ) = 5

Proof of Theorem 4p1e5

Step	Hyp	Ref	Expression
1		df-5 8995	. 2 |- 5 = ( 4 + 1 )
2	1	eqcomi 2191	1 |- ( 4 + 1 ) = 5

Syntax hints:   = wceq 1363  (class class class)co 5888   1c1 7826   + caddc 7828   4c4 8986   5c5 8987

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1457  ax-gen 1459  ax-ext 2169

This theorem depends on definitions:  df-bi 117  df-cleq 2180  df-5 8995

This theorem is referenced by:  8t7e56  9517  9t6e54  9523  ex-exp  14832  ex-fac  14833