Theorem 4p1e5 9014

Description: 4 + 1 = 5. (Contributed by Mario Carneiro, 18-Apr-2015.)

Assertion

Ref	Expression
4p1e5	|- ( 4 + 1 ) = 5

Proof of Theorem 4p1e5

Step	Hyp	Ref	Expression
1		df-5 8940	. 2 |- 5 = ( 4 + 1 )
2	1	eqcomi 2174	1 |- ( 4 + 1 ) = 5

Syntax hints:   = wceq 1348  (class class class)co 5853   1c1 7775   + caddc 7777   4c4 8931   5c5 8932

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1440  ax-gen 1442  ax-ext 2152

This theorem depends on definitions:  df-bi 116  df-cleq 2163  df-5 8940

This theorem is referenced by:  8t7e56  9462  9t6e54  9468  ex-exp  13762  ex-fac  13763