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Theorem ancomstVD 41076
Description: Closed form of ancoms 459. The following user's proof is completed by invoking mmj2's unify command and using mmj2's StepSelector to pick all remaining steps of the Metamath proof.
1:: ((𝜑𝜓) ↔ (𝜓𝜑))
qed:1,?: e0a 40983 (((𝜑𝜓) → 𝜒) ↔ ((𝜓 𝜑) → 𝜒))
The proof of ancomst 465 is derived automatically from it. (Contributed by Alan Sare, 25-Dec-2011.) (Proof modification is discouraged.) (New usage is discouraged.)
Assertion
Ref Expression
ancomstVD (((𝜑𝜓) → 𝜒) ↔ ((𝜓𝜑) → 𝜒))

Proof of Theorem ancomstVD
StepHypRef Expression
1 ancom 461 . 2 ((𝜑𝜓) ↔ (𝜓𝜑))
2 imbi1 349 . 2 (((𝜑𝜓) ↔ (𝜓𝜑)) → (((𝜑𝜓) → 𝜒) ↔ ((𝜓𝜑) → 𝜒)))
31, 2e0a 40983 1 (((𝜑𝜓) → 𝜒) ↔ ((𝜓𝜑) → 𝜒))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 207  wa 396
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This theorem depends on definitions:  df-bi 208  df-an 397
This theorem is referenced by: (None)
  Copyright terms: Public domain W3C validator