Theorem exor 43432

Description: Alias for 19.43 1915 for easier lookup. (Contributed by SN, 5-Jul-2025.) (New usage is discouraged.)

Assertion

Ref	Expression
exor	⊢ (∃𝑥(𝜑 ∨ 𝜓) ↔ (∃𝑥𝜑 ∨ ∃𝑥𝜓))

Proof of Theorem exor

Step	Hyp	Ref	Expression
1		19.43 1915	1 ⊢ (∃𝑥(𝜑 ∨ 𝜓) ↔ (∃𝑥𝜑 ∨ ∃𝑥𝜓))

This proof depends on syntax axioms:   ↔ wb 209   ∨ wo 861  ∃wex 1812

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842

This proof depends on definitions:  df-bi 210  df-or 862  df-ex 1813

This theorem is used by: (None)