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Theorem rexor 43679
Description: Alias for r19.43 3131 for easier lookup. (Contributed by SN, 5-Jul-2025.) (New usage is discouraged.)
Assertion
Ref Expression
rexor (∃𝑥 ∈ 𝐴 (𝜑 ∨ 𝜓) ↔ (∃𝑥 ∈ 𝐴 𝜑 ∨ ∃𝑥 ∈ 𝐴 𝜓))

Proof of Theorem rexor
StepHypRef Expression
1 r19.43 3131 1 (∃𝑥 ∈ 𝐴 (𝜑 ∨ 𝜓) ↔ (∃𝑥 ∈ 𝐴 𝜑 ∨ ∃𝑥 ∈ 𝐴 𝜓))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ↔ wb 209   ∨ wo 861  ∃wrex 3087
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-ex 1813  df-ral 3078  df-rex 3088
This theorem is used by: (None)
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