Theorem iscnrm3lem3 46229

Description: Lemma for iscnrm3lem4 46230. (Contributed by Zhi Wang, 4-Sep-2024.)

Assertion

Ref	Expression
iscnrm3lem3	⊢ (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) ↔ ((𝜑 ∧ 𝜒 ∧ 𝜃) ∧ 𝜓))

Proof of Theorem iscnrm3lem3

Step	Hyp	Ref	Expression
1		anass 469	. 2 ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) ↔ (𝜑 ∧ (𝜓 ∧ (𝜒 ∧ 𝜃))))
2		anass 469	. . 3 ⊢ (((𝜑 ∧ (𝜒 ∧ 𝜃)) ∧ 𝜓) ↔ (𝜑 ∧ ((𝜒 ∧ 𝜃) ∧ 𝜓)))
3		3anass 1094	. . . 4 ⊢ ((𝜑 ∧ 𝜒 ∧ 𝜃) ↔ (𝜑 ∧ (𝜒 ∧ 𝜃)))
4	3	anbi1i 624	. . 3 ⊢ (((𝜑 ∧ 𝜒 ∧ 𝜃) ∧ 𝜓) ↔ ((𝜑 ∧ (𝜒 ∧ 𝜃)) ∧ 𝜓))
5		ancom 461	. . . 4 ⊢ ((𝜓 ∧ (𝜒 ∧ 𝜃)) ↔ ((𝜒 ∧ 𝜃) ∧ 𝜓))
6	5	anbi2i 623	. . 3 ⊢ ((𝜑 ∧ (𝜓 ∧ (𝜒 ∧ 𝜃))) ↔ (𝜑 ∧ ((𝜒 ∧ 𝜃) ∧ 𝜓)))
7	2, 4, 6	3bitr4ri 304	. 2 ⊢ ((𝜑 ∧ (𝜓 ∧ (𝜒 ∧ 𝜃))) ↔ ((𝜑 ∧ 𝜒 ∧ 𝜃) ∧ 𝜓))
8	1, 7	bitri 274	1 ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) ↔ ((𝜑 ∧ 𝜒 ∧ 𝜃) ∧ 𝜓))

Syntax hints:   ↔ wb 205   ∧ wa 396   ∧ w3a 1086

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 206  df-an 397  df-3an 1088

This theorem is referenced by:  iscnrm3lem4  46230