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| Mirrors > Home > MPE Home > Th. List > nfi | Structured version Visualization version GIF version | ||
| Description: Deduce that 𝑥 is not free in 𝜑 from the definition. (Contributed by Wolf Lammen, 15-Sep-2021.) | 
| Ref | Expression | 
|---|---|
| nfi.1 | ⊢ (∃𝑥𝜑 → ∀𝑥𝜑) | 
| Ref | Expression | 
|---|---|
| nfi | ⊢ Ⅎ𝑥𝜑 | 
| Step | Hyp | Ref | Expression | 
|---|---|---|---|
| 1 | nfi.1 | . 2 ⊢ (∃𝑥𝜑 → ∀𝑥𝜑) | |
| 2 | df-nf 1783 | . 2 ⊢ (Ⅎ𝑥𝜑 ↔ (∃𝑥𝜑 → ∀𝑥𝜑)) | |
| 3 | 1, 2 | mpbir 231 | 1 ⊢ Ⅎ𝑥𝜑 | 
| Colors of variables: wff setvar class | 
| Syntax hints: → wi 4 ∀wal 1537 ∃wex 1778 Ⅎwnf 1782 | 
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 | 
| This theorem depends on definitions: df-bi 207 df-nf 1783 | 
| This theorem is referenced by: nfv 1913 | 
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