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| Mirrors > Home > MPE Home > Th. List > nfi | Structured version Visualization version GIF version | ||
| Description: Deduce that 𝑥 is not free in 𝜑 from the definition. (Contributed by Wolf Lammen, 15-Sep-2021.) |
| Ref | Expression |
|---|---|
| nfi.1 | ⊢ (∃𝑥𝜑 → ∀𝑥𝜑) |
| Ref | Expression |
|---|---|
| nfi | ⊢ Ⅎ𝑥𝜑 |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | nfi.1 | . 2 ⊢ (∃𝑥𝜑 → ∀𝑥𝜑) | |
| 2 | df-nf 1784 | . 2 ⊢ (Ⅎ𝑥𝜑 ↔ (∃𝑥𝜑 → ∀𝑥𝜑)) | |
| 3 | 1, 2 | mpbir 231 | 1 ⊢ Ⅎ𝑥𝜑 |
| Colors of variables: wff setvar class |
| Syntax hints: → wi 4 ∀wal 1538 ∃wex 1779 Ⅎwnf 1783 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 |
| This theorem depends on definitions: df-bi 207 df-nf 1784 |
| This theorem is referenced by: nfv 1914 |
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