Theorem addceq2d 4391

Description: Equality deduction for cardinal addition. (Contributed by SF, 3-Feb-2015.)

Hypothesis

Ref	Expression
addceqd.1	|- (ph -> A = B)

Assertion

Ref	Expression
addceq2d	|- (ph -> (C +o A) = (C +o B))

Proof of Theorem addceq2d

Step	Hyp	Ref	Expression
1		addceqd.1	. 2 |- (ph -> A = B)
2		addceq2 4385	. 2 |- (A = B -> (C +o A) = (C +o B))
3	1, 2	syl 15	1 |- (ph -> (C +o A) = (C +o B))

Syntax hints:   -> wi 4   = wceq 1642   +o cplc 4376

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334  ax-nin 4079  ax-sn 4088

This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-3an 936  df-nan 1288  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2340  df-cleq 2346  df-clel 2349  df-nfc 2479  df-ne 2519  df-rex 2621  df-v 2862  df-nin 3212  df-compl 3213  df-in 3214  df-un 3215  df-dif 3216  df-symdif 3217  df-ss 3260  df-nul 3552  df-pw 3725  df-sn 3742  df-pr 3743  df-opk 4059  df-1c 4137  df-pw1 4138  df-ins2k 4188  df-ins3k 4189  df-imak 4190  df-sik 4193  df-ssetk 4194  df-addc 4379

This theorem is referenced by:  nchoicelem14  6303