Theorem addceq2d 4390

Description: Equality deduction for cardinal addition. (Contributed by SF, 3-Feb-2015.)

Hypothesis

Ref	Expression
addceqd.1	⊢ (φ → A = B)

Assertion

Ref	Expression
addceq2d	⊢ (φ → (C +c A) = (C +c B))

Proof of Theorem addceq2d

Step	Hyp	Ref	Expression
1		addceqd.1	. 2 ⊢ (φ → A = B)
2		addceq2 4384	. 2 ⊢ (A = B → (C +c A) = (C +c B))
3	1, 2	syl 15	1 ⊢ (φ → (C +c A) = (C +c B))

Syntax hints:   → wi 4   = wceq 1642   +_c cplc 4375

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334  ax-nin 4078  ax-sn 4087

This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-3an 936  df-nan 1288  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2340  df-cleq 2346  df-clel 2349  df-nfc 2478  df-ne 2518  df-rex 2620  df-v 2861  df-nin 3211  df-compl 3212  df-in 3213  df-un 3214  df-dif 3215  df-symdif 3216  df-ss 3259  df-nul 3551  df-pw 3724  df-sn 3741  df-pr 3742  df-opk 4058  df-1c 4136  df-pw1 4137  df-ins2k 4187  df-ins3k 4188  df-imak 4189  df-sik 4192  df-ssetk 4193  df-addc 4378

This theorem is referenced by:  nchoicelem14  6302