NFE Home New Foundations Explorer < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  NFE Home  >  Th. List  >  bimsc1 GIF version

Theorem bimsc1 904
Description: Removal of conjunct from one side of an equivalence. (Contributed by NM, 5-Aug-1993.)
Assertion
Ref Expression
bimsc1 ⊢ (((φ → ψ) ∧ (χ ↔ (ψ ∧ φ))) → (χ ↔ φ))

Proof of Theorem bimsc1
StepHypRef Expression
1 simpr 447 . . . 4 ⊢ ((ψ ∧ φ) → φ)
2 ancr 532 . . . 4 ⊢ ((φ → ψ) → (φ → (ψ ∧ φ)))
31, 2impbid2 195 . . 3 ⊢ ((φ → ψ) → ((ψ ∧ φ) ↔ φ))
43bibi2d 309 . 2 ⊢ ((φ → ψ) → ((χ ↔ (ψ ∧ φ)) ↔ (χ ↔ φ)))
54biimpa 470 1 ⊢ (((φ → ψ) ∧ (χ ↔ (ψ ∧ φ))) → (χ ↔ φ))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 176   ∧ wa 358
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 177  df-an 360
This theorem is used by: (None)
  Copyright terms: Public domain W3C validator