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Theorem dn1 932
Description: A single axiom for Boolean algebra known as DN1. See http://www-unix.mcs.anl.gov/~mccune/papers/basax/v12.pdf. (Contributed by Jeffrey Hankins, 3-Jul-2009.) (Proof shortened by Andrew Salmon, 13-May-2011.) (Proof shortened by Wolf Lammen, 6-Jan-2013.)
Assertion
Ref Expression
dn1 ⊢ (¬ (¬ (¬ (φ ∨ ψ) ∨ χ) ∨ ¬ (φ ∨ ¬ (¬ χ ∨ ¬ (χ ∨ θ)))) ↔ χ)

Proof of Theorem dn1
StepHypRef Expression
1 pm2.45 386 . . . . 5 ⊢ (¬ (φ ∨ ψ) → ¬ φ)
2 imnan 411 . . . . 5 ⊢ ((¬ (φ ∨ ψ) → ¬ φ) ↔ ¬ (¬ (φ ∨ ψ) ∧ φ))
31, 2mpbi 199 . . . 4 ⊢ ¬ (¬ (φ ∨ ψ) ∧ φ)
43biorfi 396 . . 3 ⊢ (χ ↔ (χ ∨ (¬ (φ ∨ ψ) ∧ φ)))
5 orcom 376 . . . 4 ⊢ ((χ ∨ (¬ (φ ∨ ψ) ∧ φ)) ↔ ((¬ (φ ∨ ψ) ∧ φ) ∨ χ))
6 ordir 835 . . . 4 ⊢ (((¬ (φ ∨ ψ) ∧ φ) ∨ χ) ↔ ((¬ (φ ∨ ψ) ∨ χ) ∧ (φ ∨ χ)))
75, 6bitri 240 . . 3 ⊢ ((χ ∨ (¬ (φ ∨ ψ) ∧ φ)) ↔ ((¬ (φ ∨ ψ) ∨ χ) ∧ (φ ∨ χ)))
84, 7bitri 240 . 2 ⊢ (χ ↔ ((¬ (φ ∨ ψ) ∨ χ) ∧ (φ ∨ χ)))
9 pm4.45 669 . . . . 5 ⊢ (χ ↔ (χ ∧ (χ ∨ θ)))
10 anor 475 . . . . 5 ⊢ ((χ ∧ (χ ∨ θ)) ↔ ¬ (¬ χ ∨ ¬ (χ ∨ θ)))
119, 10bitri 240 . . . 4 ⊢ (χ ↔ ¬ (¬ χ ∨ ¬ (χ ∨ θ)))
1211orbi2i 505 . . 3 ⊢ ((φ ∨ χ) ↔ (φ ∨ ¬ (¬ χ ∨ ¬ (χ ∨ θ))))
1312anbi2i 675 . 2 ⊢ (((¬ (φ ∨ ψ) ∨ χ) ∧ (φ ∨ χ)) ↔ ((¬ (φ ∨ ψ) ∨ χ) ∧ (φ ∨ ¬ (¬ χ ∨ ¬ (χ ∨ θ)))))
14 anor 475 . 2 ⊢ (((¬ (φ ∨ ψ) ∨ χ) ∧ (φ ∨ ¬ (¬ χ ∨ ¬ (χ ∨ θ)))) ↔ ¬ (¬ (¬ (φ ∨ ψ) ∨ χ) ∨ ¬ (φ ∨ ¬ (¬ χ ∨ ¬ (χ ∨ θ)))))
158, 13, 143bitrri 263 1 ⊢ (¬ (¬ (¬ (φ ∨ ψ) ∨ χ) ∨ ¬ (φ ∨ ¬ (¬ χ ∨ ¬ (χ ∨ θ)))) ↔ χ)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3   → wi 4   ↔ wb 176   ∨ wo 357   ∧ wa 358
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 177  df-or 359  df-an 360
This theorem is used by: (None)
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