Theorem lem3.4.1 1075

Description: Equation 3.9 of [PavMeg1999] p. 9. (Contributed by Roy F. Longton, 3-Jul-2005.)

Assertion

Ref	Expression
lem3.4.1	((a →1 b) →0 (a →2 b)) = 1

Proof of Theorem lem3.4.1

Step	Hyp	Ref	Expression
1		df-i0 43	. 2 ((a →1 b) →0 (a →2 b)) = ((a →1 b)⊥ ∪ (a →2 b))
2		woml6 436	. 2 ((a →1 b)⊥ ∪ (a →2 b)) = 1
3	1, 2	ax-r2 36	1 ((a →1 b) →0 (a →2 b)) = 1

Syntax hints:   = wb 1  ^⊥ wn 4   ∪ wo 6  1wt 8   →₀ wi0 11   →₁ wi1 12   →₂ wi2 13

This theorem was proved from axioms:  ax-a1 30  ax-a2 31  ax-a3 32  ax-a4 33  ax-a5 34  ax-r1 35  ax-r2 36  ax-r4 37  ax-r5 38  ax-wom 361

This theorem depends on definitions:  df-b 39  df-a 40  df-t 41  df-f 42  df-i0 43  df-i1 44  df-i2 45  df-le 129  df-le1 130  df-le2 131  df-cmtr 134

This theorem is referenced by: (None)