Theorem 1p0e1 9429

Description: 1 + 0 = 1. (Contributed by David A. Wheeler, 8-Dec-2018.)

Assertion

Ref	Expression
1p0e1	|- ( 1 + 0 ) = 1

Proof of Theorem 1p0e1

Step	Hyp	Ref	Expression
1		ax-1cn 8278	. 2 |- 1 e. CC
2	1	addridi 8475	1 |- ( 1 + 0 ) = 1

This proof depends on syntax axioms:   = wceq 1402  (class class class)co 6088   0cc0 8185   1c1 8186   + caddc 8188

This proof depends on axioms:  ax-mp 5  ax-1cn 8278  ax-0id 8293

This theorem is used by:  bernneq  11118  bcpasc  11225  4sqlem19  13216  1259lem1  13270  ballotfilemic  13307  ef2pi  16049  1sgm2ppw  16306