Theorem 1p0e1 9423

Description: 1 + 0 = 1. (Contributed by David A. Wheeler, 8-Dec-2018.)

Assertion

Ref	Expression
1p0e1	|- ( 1 + 0 ) = 1

Proof of Theorem 1p0e1

Step	Hyp	Ref	Expression
1		ax-1cn 8273	. 2 |- 1 e. CC
2	1	addridi 8470	1 |- ( 1 + 0 ) = 1

This proof depends on syntax axioms:   = wceq 1402  (class class class)co 6085   0cc0 8180   1c1 8181   + caddc 8183

This proof depends on axioms:  ax-mp 5  ax-1cn 8273  ax-0id 8288

This theorem is used by:  bernneq  11113  bcpasc  11220  4sqlem19  13211  1259lem1  13265  ballotfilemic  13302  ef2pi  15998  1sgm2ppw  16250