Theorem 5p1e6 9128

Description: 5 + 1 = 6. (Contributed by Mario Carneiro, 18-Apr-2015.)

Assertion

Ref	Expression
5p1e6	|- ( 5 + 1 ) = 6

Proof of Theorem 5p1e6

Step	Hyp	Ref	Expression
1		df-6 9053	. 2 |- 6 = ( 5 + 1 )
2	1	eqcomi 2200	1 |- ( 5 + 1 ) = 6

Syntax hints:   = wceq 1364  (class class class)co 5922   1c1 7880   + caddc 7882   5c5 9044   6c6 9045

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1461  ax-gen 1463  ax-ext 2178

This theorem depends on definitions:  df-bi 117  df-cleq 2189  df-6 9053

This theorem is referenced by:  8t8e64  9577  9t7e63  9583  5recm6rec  9600  fldiv4p1lem1div2  10395  5ndvds6  12100