Theorem spimfv 1699

Description: Specialization, using implicit substitution. Version of spim 1738 with a disjoint variable condition. See spimv 1811 for another variant. (Contributed by NM, 10-Jan-1993.) (Revised by BJ, 31-May-2019.)

Hypotheses

Ref	Expression
spimfv.nf	|- F/ x ps
spimfv.1	|- ( x = y -> ( ph -> ps ) )

Assertion

Ref	Expression
spimfv	|- ( A. x ph -> ps )

Distinct variable group:   x, y

Allowed substitution hints:   ph( x, y)   ps( x, y)

Proof of Theorem spimfv

Step	Hyp	Ref	Expression
1		spimfv.nf	. 2 |- F/ x ps
2		a9ev 1697	. . 3 |- E. x x = y
3		spimfv.1	. . 3 |- ( x = y -> ( ph -> ps ) )
4	2, 3	eximii 1602	. 2 |- E. x ( ph -> ps )
5	1, 4	19.36i 1672	1 |- ( A. x ph -> ps )

Syntax hints:   -> wi 4   A.wal 1351   F/wnf 1460

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1447  ax-gen 1449  ax-ie1 1493  ax-ie2 1494  ax-4 1510  ax-i9 1530  ax-ial 1534

This theorem depends on definitions:  df-bi 117  df-nf 1461

This theorem is referenced by:  chvarfv  1700