Theorem 3expd 1224

Description: Exportation deduction for triple conjunction. (Contributed by NM, 26-Oct-2006.)

Hypothesis

Ref	Expression
3expd.1	⊢ (𝜑 → ((𝜓 ∧ 𝜒 ∧ 𝜃) → 𝜏))

Assertion

Ref	Expression
3expd	⊢ (𝜑 → (𝜓 → (𝜒 → (𝜃 → 𝜏))))

Proof of Theorem 3expd

Step	Hyp	Ref	Expression
1		3expd.1	. . . 4 ⊢ (𝜑 → ((𝜓 ∧ 𝜒 ∧ 𝜃) → 𝜏))
2	1	com12 30	. . 3 ⊢ ((𝜓 ∧ 𝜒 ∧ 𝜃) → (𝜑 → 𝜏))
3	2	3exp 1202	. 2 ⊢ (𝜓 → (𝜒 → (𝜃 → (𝜑 → 𝜏))))
4	3	com4r 86	1 ⊢ (𝜑 → (𝜓 → (𝜒 → (𝜃 → 𝜏))))

Syntax hints:   → wi 4   ∧ w3a 978

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108

This theorem depends on definitions:  df-bi 117  df-3an 980

This theorem is referenced by:  3exp2  1225  exp516  1227  3impexp  1435  3impexpbicom  1436  mulgnnass  12878