Theorem 3expd 1225

Description: Exportation deduction for triple conjunction. (Contributed by NM, 26-Oct-2006.)

Hypothesis

Ref	Expression
3expd.1	|- ( ph -> ( ( ps /\ ch /\ th ) -> ta ) )

Assertion

Ref	Expression
3expd	|- ( ph -> ( ps -> ( ch -> ( th -> ta ) ) ) )

Proof of Theorem 3expd

Step	Hyp	Ref	Expression
1		3expd.1	. . . 4 |- ( ph -> ( ( ps /\ ch /\ th ) -> ta ) )
2	1	com12 30	. . 3 |- ( ( ps /\ ch /\ th ) -> ( ph -> ta ) )
3	2	3exp 1203	. 2 |- ( ps -> ( ch -> ( th -> ( ph -> ta ) ) ) )
4	3	com4r 86	1 |- ( ph -> ( ps -> ( ch -> ( th -> ta ) ) ) )

Syntax hints:   -> wi 4   /\ w3a 979

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108

This theorem depends on definitions:  df-bi 117  df-3an 981

This theorem is referenced by:  3exp2  1226  exp516  1228  3impexp  1447  3impexpbicom  1448  mulgnnass  13062