Theorem pm5.32rd 455

Description: Distribution of implication over biconditional (deduction form). (Contributed by NM, 25-Dec-2004.)

Hypothesis

Ref	Expression
pm5.32d.1	⊢ (𝜑 → (𝜓 → (𝜒 ↔ 𝜃)))

Assertion

Ref	Expression
pm5.32rd	⊢ (𝜑 → ((𝜒 ∧ 𝜓) ↔ (𝜃 ∧ 𝜓)))

Proof of Theorem pm5.32rd

Step	Hyp	Ref	Expression
1		pm5.32d.1	. . 3 ⊢ (𝜑 → (𝜓 → (𝜒 ↔ 𝜃)))
2	1	pm5.32d 454	. 2 ⊢ (𝜑 → ((𝜓 ∧ 𝜒) ↔ (𝜓 ∧ 𝜃)))
3		ancom 266	. 2 ⊢ ((𝜒 ∧ 𝜓) ↔ (𝜓 ∧ 𝜒))
4		ancom 266	. 2 ⊢ ((𝜃 ∧ 𝜓) ↔ (𝜓 ∧ 𝜃))
5	2, 3, 4	3bitr4g 223	1 ⊢ (𝜑 → ((𝜒 ∧ 𝜓) ↔ (𝜃 ∧ 𝜓)))

This proof depends on syntax axioms:   → wi 4   ∧ wa 104   ↔ wb 105

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108

This proof depends on definitions:  df-bi 117

This theorem is used by:  anbi1d  469  pm5.71dc  974  1idprl  7958  1idpru  7959  4sqexercise2  13201  4sqlemsdc  13202  psrbaglefifi  15147  isclwwlknx  16823  clwwlknonel  16839  eupth2lem3lem6fi  16878