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Theorem bnj268 35340
Description: ∧-manipulation. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) (New usage is discouraged.)
Assertion
Ref Expression
bnj268 ((𝜑 ∧ 𝜓 ∧ 𝜒 ∧ 𝜃) ↔ (𝜑 ∧ 𝜒 ∧ 𝜓 ∧ 𝜃))

Proof of Theorem bnj268
StepHypRef Expression
1 3ancomb 1116 . . 3 ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ (𝜑 ∧ 𝜒 ∧ 𝜓))
21anbi1i 636 . 2 (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃) ↔ ((𝜑 ∧ 𝜒 ∧ 𝜓) ∧ 𝜃))
3 df-bnj17 35318 . 2 ((𝜑 ∧ 𝜓 ∧ 𝜒 ∧ 𝜃) ↔ ((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃))
4 df-bnj17 35318 . 2 ((𝜑 ∧ 𝜒 ∧ 𝜓 ∧ 𝜃) ↔ ((𝜑 ∧ 𝜒 ∧ 𝜓) ∧ 𝜃))
52, 3, 43bitr4i 306 1 ((𝜑 ∧ 𝜓 ∧ 𝜒 ∧ 𝜃) ↔ (𝜑 ∧ 𝜒 ∧ 𝜓 ∧ 𝜃))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ↔ wb 209   ∧ wa 401   ∧ w3a 1103   ∧ w-bnj17 35317
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 210  df-an 402  df-3an 1105  df-bnj17 35318
This theorem is used by:  bnj543  35523  bnj929  35566  bnj1110  35612
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