Theorem eliminable-velab 36825

Description: A theorem used to prove the base case of the Eliminability Theorem (see section comment): variable belongs to abstraction. (Contributed by BJ, 30-Apr-2024.) (Proof modification is discouraged.) (New usage is discouraged.)

Assertion

Ref	Expression
eliminable-velab	⊢ (𝑦 ∈ {𝑥 ∣ 𝜑} ↔ [𝑦 / 𝑥]𝜑)

Proof of Theorem eliminable-velab

Step	Hyp	Ref	Expression
1		df-clab 2713	1 ⊢ (𝑦 ∈ {𝑥 ∣ 𝜑} ↔ [𝑦 / 𝑥]𝜑)

Syntax hints:   ↔ wb 206  [wsb 2063   ∈ wcel 2107  {cab 2712

This theorem depends on definitions:  df-clab 2713

This theorem is referenced by:  eliminable-veqab  36826  eliminable-abeqv  36827  eliminable-abeqab  36828  eliminable-abelab  36830