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Theorem List for Metamath Proof Explorer - 36401-36500   *Has distinct variable group(s)
TypeLabelDescription
Statement

Theoremcdleme7e 36401 Part of proof of Lemma E in [Crawley] p. 113. Lemma leading to cdleme7ga 36402 and cdleme7 36403. (Contributed by NM, 8-Jun-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑃 𝑄) (𝐹 ((𝑅 𝑆) 𝑊)))    &   𝑉 = ((𝑅 𝑆) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ (𝑃𝑄𝑅 (𝑃 𝑄) ∧ ¬ 𝑆 (𝑃 𝑄))) → 𝐺 ≠ (0.‘𝐾))

Theoremcdleme7ga 36402 Part of proof of Lemma E in [Crawley] p. 113. See cdleme7 36403. (Contributed by NM, 8-Jun-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑃 𝑄) (𝐹 ((𝑅 𝑆) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ (𝑃𝑄𝑅 (𝑃 𝑄) ∧ ¬ 𝑆 (𝑃 𝑄))) → 𝐺𝐴)

Theoremcdleme7 36403 Part of proof of Lemma E in [Crawley] p. 113. 𝐺 and 𝐹 represent fs(r) and f(s) respectively. 𝑊 is the fiducial co-atom (hyperplane) that they call w. Here and in cdleme7ga 36402 above, we show that fs(r) W (top of p. 114), meaning it is an atom and not under w, which in our notation is expressed as 𝐺𝐴 ∧ ¬ 𝐺 𝑊. (Note that we do not have a symbol for their W.) Their proof provides no details of our cdleme7aa 36396 through cdleme7 36403, so there may be a simpler proof that we have overlooked. (Contributed by NM, 9-Jun-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑃 𝑄) (𝐹 ((𝑅 𝑆) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ (𝑃𝑄𝑅 (𝑃 𝑄) ∧ ¬ 𝑆 (𝑃 𝑄))) → ¬ 𝐺 𝑊)

Theoremcdleme8 36404 Part of proof of Lemma E in [Crawley] p. 113, 2nd paragraph on p. 114. 𝐶 represents s1. In their notation, we prove p s1 = p s. (Contributed by NM, 9-Jun-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝐶 = ((𝑃 𝑆) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑆𝐴) → (𝑃 𝐶) = (𝑃 𝑆))

Theoremcdleme9a 36405 Part of proof of Lemma E in [Crawley] p. 113. 𝐶 represents s1, which we prove is an atom. (Contributed by NM, 10-Jun-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝐶 = ((𝑃 𝑆) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑆𝐴𝑃𝑆)) → 𝐶𝐴)

Theoremcdleme9b 36406 Utility lemma for Lemma E in [Crawley] p. 113. (Contributed by NM, 9-Oct-2012.)
𝐵 = (Base‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝐶 = ((𝑃 𝑆) 𝑊)       ((𝐾 ∈ HL ∧ (𝑃𝐴𝑆𝐴𝑊𝐻)) → 𝐶𝐵)

Theoremcdleme9 36407 Part of proof of Lemma E in [Crawley] p. 113, 2nd paragraph on p. 114. 𝐶 and 𝐹 represent s1 and f(s) respectively. In their notation, we prove f(s) s1 = q s1. (Contributed by NM, 10-Jun-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐶 = ((𝑃 𝑆) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴 ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ ¬ 𝑆 (𝑃 𝑄)) → (𝐹 𝐶) = (𝑄 𝐶))

Theoremcdleme10 36408 Part of proof of Lemma E in [Crawley] p. 113, 2nd paragraph on p. 114. 𝐷 represents s2. In their notation, we prove s s2 = s r. (Contributed by NM, 9-Jun-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝐷 = ((𝑅 𝑆) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝑅𝐴 ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) → (𝑆 𝐷) = (𝑆 𝑅))

Theoremcdleme8tN 36409 Part of proof of Lemma E in [Crawley] p. 113, 2nd paragraph on p. 114. 𝑋 represents t1. In their notation, we prove p t1 = p t. (Contributed by NM, 8-Oct-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑋 = ((𝑃 𝑇) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑇𝐴) → (𝑃 𝑋) = (𝑃 𝑇))

Theoremcdleme9taN 36410 Part of proof of Lemma E in [Crawley] p. 113. 𝑋 represents t1, which we prove is an atom. (Contributed by NM, 8-Oct-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑋 = ((𝑃 𝑇) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑇𝐴𝑃𝑇)) → 𝑋𝐴)

Theoremcdleme9tN 36411 Part of proof of Lemma E in [Crawley] p. 113, 2nd paragraph on p. 114. 𝑋 and 𝐹 represent t1 and f(t) respectively. In their notation, we prove f(t) t1 = q t1. (Contributed by NM, 8-Oct-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝑋 = ((𝑃 𝑇) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴 ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ¬ 𝑇 (𝑃 𝑄)) → (𝐹 𝑋) = (𝑄 𝑋))

Theoremcdleme10tN 36412 Part of proof of Lemma E in [Crawley] p. 113, 2nd paragraph on p. 114. 𝑌 represents t2. In their notation, we prove t t2 = t r. (Contributed by NM, 8-Oct-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑌 = ((𝑅 𝑇) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝑅𝐴 ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) → (𝑇 𝑌) = (𝑇 𝑅))

Theoremcdleme16aN 36413 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph on p. 114, showing, in their notation, s u t u. (Contributed by NM, 9-Oct-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) ∧ (𝑄𝐴𝑆𝐴𝑇𝐴) ∧ (𝑃𝑄𝑆𝑇 ∧ ¬ 𝑈 (𝑆 𝑇))) → (𝑆 𝑈) ≠ (𝑇 𝑈))

Theoremcdleme11a 36414 Part of proof of Lemma E in [Crawley] p. 113. Lemma leading to cdleme11 36424. (Contributed by NM, 12-Jun-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴𝑃𝑄)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴𝑈 (𝑆 𝑇)))) → (𝑆 𝑈) = (𝑆 𝑇))

Theoremcdleme11c 36415 Part of proof of Lemma E in [Crawley] p. 113. Lemma leading to cdleme11 36424. (Contributed by NM, 13-Jun-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ 𝑇𝐴𝑃𝑄) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ 𝑈 (𝑆 𝑇))) → ¬ 𝑃 (𝑆 𝑇))

Theoremcdleme11dN 36416 Part of proof of Lemma E in [Crawley] p. 113. Lemma leading to cdleme11 36424. (Contributed by NM, 13-Jun-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ 𝑇𝐴𝑃𝑄) ∧ (𝑆𝑇 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ 𝑈 (𝑆 𝑇))) → (𝑃 𝑆) ≠ (𝑃 𝑇))

Theoremcdleme11e 36417 Part of proof of Lemma E in [Crawley] p. 113. Lemma leading to cdleme11 36424. (Contributed by NM, 13-Jun-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐶 = ((𝑃 𝑆) 𝑊)    &   𝐷 = ((𝑃 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ 𝑇𝐴𝑃𝑄) ∧ (𝑆𝑇 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ 𝑈 (𝑆 𝑇))) → 𝐶𝐷)

Theoremcdleme11fN 36418 Part of proof of Lemma E in [Crawley] p. 113. Lemma leading to cdleme11 36424. (Contributed by NM, 14-Jun-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐶 = ((𝑃 𝑆) 𝑊)    &   𝐷 = ((𝑃 𝑇) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄))) → 𝐹𝐶)

Theoremcdleme11g 36419 Part of proof of Lemma E in [Crawley] p. 113. Lemma leading to cdleme11 36424. (Contributed by NM, 14-Jun-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐶 = ((𝑃 𝑆) 𝑊)    &   𝐷 = ((𝑃 𝑇) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ 𝑆𝐴) ∧ 𝑃𝑄) → (𝑄 𝐹) = (𝑄 𝐶))

Theoremcdleme11h 36420 Part of proof of Lemma E in [Crawley] p. 113. Lemma leading to cdleme11 36424. (Contributed by NM, 14-Jun-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐶 = ((𝑃 𝑆) 𝑊)    &   𝐷 = ((𝑃 𝑇) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ 𝑆𝐴) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄))) → 𝐹𝑄)

Theoremcdleme11j 36421 Part of proof of Lemma E in [Crawley] p. 113. Lemma leading to cdleme11 36424. (Contributed by NM, 14-Jun-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐶 = ((𝑃 𝑆) 𝑊)    &   𝐷 = ((𝑃 𝑇) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄))) → 𝐶 (𝑄 𝐹))

Theoremcdleme11k 36422 Part of proof of Lemma E in [Crawley] p. 113. Lemma leading to cdleme11 36424. (Contributed by NM, 15-Jun-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐶 = ((𝑃 𝑆) 𝑊)    &   𝐷 = ((𝑃 𝑇) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄))) → 𝐶 = ((𝑄 𝐹) 𝑊))

Theoremcdleme11l 36423 Part of proof of Lemma E in [Crawley] p. 113. Lemma leading to cdleme11 36424. (Contributed by NM, 15-Jun-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄𝑆𝑇)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑈 (𝑆 𝑇))) → 𝐹𝐺)

Theoremcdleme11 36424 Part of proof of Lemma E in [Crawley] p. 113, 1st sentence of 3rd paragraph on p. 114. 𝐹 and 𝐺 represent f(s) and f(t) respectively. Their proof provides no details of our cdleme11a 36414 through cdleme11 36424, so there may be a simpler proof that we have overlooked. (Contributed by NM, 15-Jun-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄𝑆𝑇)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑈 (𝑆 𝑇))) → (𝐹 𝐺) = (𝑆 𝑇))

Theoremcdleme12 36425 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph on p. 114, first part of 3rd sentence. 𝐹 and 𝐺 represent f(s) and f(t) respectively. (Contributed by NM, 16-Jun-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴𝑃𝑄) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑆𝑇 ∧ ¬ 𝑈 (𝑆 𝑇)))) → ((𝑆 𝐹) (𝑇 𝐺)) = 𝑈)

Theoremcdleme13 36426 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph on p. 114, "<s,t,p> and <f(s),f(t),q> are centrally perspective." 𝐹 and 𝐺 represent f(s) and f(t) respectively. (Contributed by NM, 7-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴𝑃𝑄) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑆𝑇 ∧ ¬ 𝑈 (𝑆 𝑇)))) → ((𝑆 𝐹) (𝑇 𝐺)) (𝑃 𝑄))

Theoremcdleme14 36427 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph on p. 114, "<s,t,p> and <f(s),f(t),q> ... are axially perspective." We apply dalaw 36040 to cdleme13 36426. 𝐹 and 𝐺 represent f(s) and f(t) respectively. (Contributed by NM, 8-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄𝑆𝑇)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ ¬ 𝑈 (𝑆 𝑇))) → ((𝑆 𝑇) (𝐹 𝐺)) (((𝑇 𝑃) (𝐺 𝑄)) ((𝑃 𝑆) (𝑄 𝐹))))

Theoremcdleme15a 36428 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph on p. 114, showing, in their notation, ((s p) (f(s) q)) ((t p) (f(t) q))=((p s1) (q s1)) ((p t1) (q t1)). We represent f(s), f(t), s1, and t1 with 𝐹, 𝐺, 𝐶, and 𝑋 respectively. The order of our operations is slightly different. (Contributed by NM, 9-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐶 = ((𝑃 𝑆) 𝑊)    &   𝑋 = ((𝑃 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄𝑆𝑇)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ ¬ 𝑈 (𝑆 𝑇))) → (((𝑇 𝑃) (𝐺 𝑄)) ((𝑃 𝑆) (𝑄 𝐹))) = (((𝑃 𝑋) (𝑄 𝑋)) ((𝑃 𝐶) (𝑄 𝐶))))

Theoremcdleme15b 36429 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph on p. 114, showing, in their notation, (p s1) (q s1)=s1. We represent s1 with 𝐶. (Contributed by NM, 10-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐶 = ((𝑃 𝑆) 𝑊)    &   𝑋 = ((𝑃 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄𝑆𝑇)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ ¬ 𝑈 (𝑆 𝑇))) → ((𝑃 𝐶) (𝑄 𝐶)) = 𝐶)

Theoremcdleme15c 36430 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph on p. 114, showing, in their notation, ((p s1) (q s1)) ((p t1) (q t1))=s1 t1. 𝐶 and 𝑋 represent s1 and t1 respectively. The order of our operations is slightly different. (Contributed by NM, 10-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐶 = ((𝑃 𝑆) 𝑊)    &   𝑋 = ((𝑃 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄𝑆𝑇)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ ¬ 𝑈 (𝑆 𝑇))) → (((𝑃 𝑋) (𝑄 𝑋)) ((𝑃 𝐶) (𝑄 𝐶))) = (𝑋 𝐶))

Theoremcdleme15d 36431 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph on p. 114, showing, in their notation, s1 t1 w. 𝐶 and 𝑋 represent s1 and t1 respectively. The order of our operations is slightly different. (Contributed by NM, 10-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐶 = ((𝑃 𝑆) 𝑊)    &   𝑋 = ((𝑃 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄𝑆𝑇)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ ¬ 𝑈 (𝑆 𝑇))) → (𝑋 𝐶) 𝑊)

Theoremcdleme15 36432 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph on p. 114, showing, in their notation, (s t) (f(s) f(t)) w. We use 𝐹, 𝐺 for f(s), f(t) respectively. (Contributed by NM, 10-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄𝑆𝑇)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ ¬ 𝑈 (𝑆 𝑇))) → ((𝑆 𝑇) (𝐹 𝐺)) 𝑊)

Theoremcdleme16b 36433 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph on p. 114, first part of 3rd sentence. 𝐹 and 𝐺 represent f(s) and f(t) respectively. It is unclear how this follows from s u t u, as the authors state, and we used a different proof. (Note: the antecedent ¬ 𝑇 (𝑃 𝑄) is not used.) (Contributed by NM, 11-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄𝑆𝑇)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ ¬ 𝑈 (𝑆 𝑇))) → 𝐹𝐺)

Theoremcdleme16c 36434 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph on p. 114, 2nd part of 3rd sentence. 𝐹 and 𝐺 represent f(s) and f(t) respectively. We show, in their notation, s t f(s) f(t)=s t u. (Contributed by NM, 11-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄𝑆𝑇)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ ¬ 𝑈 (𝑆 𝑇))) → ((𝑆 𝑇) (𝐹 𝐺)) = ((𝑆 𝑇) 𝑈))

Theoremcdleme16d 36435 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph on p. 114, 3rd part of 3rd sentence. 𝐹 and 𝐺 represent f(s) and f(t) respectively. We show, in their notation, (s t) (f(s) f(t)) is an atom. (Contributed by NM, 11-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄𝑆𝑇)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ ¬ 𝑈 (𝑆 𝑇))) → ((𝑆 𝑇) (𝐹 𝐺)) ∈ 𝐴)

Theoremcdleme16e 36436 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph on p. 114, 3rd part of 3rd sentence. 𝐹 and 𝐺 represent f(s) and f(t) respectively. We show, in their notation, (s t) (f(s) f(t))=(s t) w. (Contributed by NM, 11-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄𝑆𝑇)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ ¬ 𝑈 (𝑆 𝑇))) → ((𝑆 𝑇) (𝐹 𝐺)) = ((𝑆 𝑇) 𝑊))

Theoremcdleme16f 36437 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph on p. 114, 3rd part of 3rd sentence. 𝐹 and 𝐺 represent f(s) and f(t) respectively. We show, in their notation, (s t) (f(s) f(t))=(f(s) f(t)) w. (Contributed by NM, 11-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄𝑆𝑇)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ ¬ 𝑈 (𝑆 𝑇))) → ((𝑆 𝑇) (𝐹 𝐺)) = ((𝐹 𝐺) 𝑊))

Theoremcdleme16g 36438 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph on p. 114, Eq. (1). 𝐹 and 𝐺 represent f(s) and f(t) respectively. We show, in their notation, (s t) w=(f(s) f(t)) w. (Contributed by NM, 11-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄𝑆𝑇)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ ¬ 𝑈 (𝑆 𝑇))) → ((𝑆 𝑇) 𝑊) = ((𝐹 𝐺) 𝑊))

Theoremcdleme16 36439 Part of proof of Lemma E in [Crawley] p. 113, conclusion of 3rd paragraph on p. 114. 𝐹 and 𝐺 represent f(s) and f(t) respectively. We show, in their notation, (s t) w=(f(s) f(t)) w, whether or not u s t. (Contributed by NM, 11-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄𝑆𝑇)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄))) → ((𝑆 𝑇) 𝑊) = ((𝐹 𝐺) 𝑊))

Theoremcdleme17a 36440 Part of proof of Lemma E in [Crawley] p. 114, first part of 4th paragraph. 𝐹, 𝐺, and 𝐶 represent f(s), fs(p), and s1 respectively. We show, in their notation, fs(p)=(p q) (q s1). (Contributed by NM, 11-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑃 𝑄) (𝐹 ((𝑃 𝑆) 𝑊)))    &   𝐶 = ((𝑃 𝑆) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴 ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ ¬ 𝑆 (𝑃 𝑄)) → 𝐺 = ((𝑃 𝑄) (𝑄 𝐶)))

Theoremcdleme17b 36441 Lemma leading to cdleme17c 36442. (Contributed by NM, 11-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑃 𝑄) (𝐹 ((𝑃 𝑆) 𝑊)))    &   𝐶 = ((𝑃 𝑆) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴𝑆𝐴 ∧ ¬ 𝑆 (𝑃 𝑄))) → ¬ 𝐶 (𝑃 𝑄))

Theoremcdleme17c 36442 Part of proof of Lemma E in [Crawley] p. 114, first part of 4th paragraph. 𝐶 represents s1. We show, in their notation, (p q) (q s1)=q. (Contributed by NM, 11-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑃 𝑄) (𝐹 ((𝑃 𝑆) 𝑊)))    &   𝐶 = ((𝑃 𝑆) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴𝑆𝐴 ∧ ¬ 𝑆 (𝑃 𝑄))) → ((𝑃 𝑄) (𝑄 𝐶)) = 𝑄)

Theoremcdleme17d1 36443 Part of proof of Lemma E in [Crawley] p. 114, first part of 4th paragraph. 𝐹, 𝐺 represent f(s), fs(p) respectively. We show, in their notation, fs(p)=q. (Contributed by NM, 11-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑃 𝑄) (𝐹 ((𝑃 𝑆) 𝑊)))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴 ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ ¬ 𝑆 (𝑃 𝑄)) → 𝐺 = 𝑄)

Theoremcdleme0nex 36444* Part of proof of Lemma E in [Crawley] p. 114, 4th line of 4th paragraph. Whenever (in their terminology) p q/0 (i.e. the sublattice from 0 to p q) contains precisely three atoms, any atom not under w must equal either p or q. (In case of 3 atoms, one of them must be u - see cdleme0a 36365- which is under w, so the only 2 left not under w are p and q themselves.) Note that by cvlsupr2 35497, our (𝑃 𝑟) = (𝑄 𝑟) is a shorter way to express 𝑟𝑃𝑟𝑄𝑟 (𝑃 𝑄). Thus, the negated existential condition states there are no atoms different from p or q that are also not under w. (Contributed by NM, 12-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &   𝐴 = (Atoms‘𝐾)       (((𝐾 ∈ HL ∧ 𝑅 (𝑃 𝑄) ∧ ¬ ∃𝑟𝐴𝑟 𝑊 ∧ (𝑃 𝑟) = (𝑄 𝑟))) ∧ (𝑃𝐴𝑄𝐴𝑃𝑄) ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊)) → (𝑅 = 𝑃𝑅 = 𝑄))

Theoremcdleme18a 36445 Part of proof of Lemma E in [Crawley] p. 114, 2nd sentence of 4th paragraph. 𝐹, 𝐺 represent f(s), fs(q) respectively. We show ¬ fs(q) w. (Contributed by NM, 12-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑃 𝑄) (𝐹 ((𝑄 𝑆) 𝑊)))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄))) → ¬ 𝐺 𝑊)

Theoremcdleme18b 36446 Part of proof of Lemma E in [Crawley] p. 114, 2nd sentence of 4th paragraph. 𝐹, 𝐺 represent f(s), fs(q) respectively. We show ¬ fs(q) q. (Contributed by NM, 12-Oct-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑃 𝑄) (𝐹 ((𝑄 𝑆) 𝑊)))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄))) → 𝐺𝑄)

Theoremcdleme18c 36447* Part of proof of Lemma E in [Crawley] p. 114, 2nd sentence of 4th paragraph. 𝐹, 𝐺 represent f(s), fs(q) respectively. We show ¬ fs(q) = p whenever p q has three atoms under it (implied by the negated existential condition). (Contributed by NM, 10-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑃 𝑄) (𝐹 ((𝑄 𝑆) 𝑊)))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ ¬ ∃𝑟𝐴𝑟 𝑊 ∧ (𝑃 𝑟) = (𝑄 𝑟)))) → 𝐺 = 𝑃)

Theoremcdleme22gb 36448 Utility lemma for Lemma E in [Crawley] p. 115. (Contributed by NM, 5-Dec-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑃 𝑄) (𝐹 ((𝑅 𝑆) 𝑊)))    &   𝐵 = (Base‘𝐾)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴𝑄𝐴) ∧ (𝑅𝐴𝑆𝐴)) → 𝐺𝐵)

Theoremcdleme18d 36449* Part of proof of Lemma E in [Crawley] p. 114, 4th sentence of 4th paragraph. 𝐹, 𝐺, 𝐷, 𝐸 represent f(s), fs(r), f(t), ft(r) respectively. We show fs(r)=ft(r) for all possible r (which must equal p or q in the case of exactly 3 atoms in p q/0 i.e. when ¬ ∃𝑟𝐴...). (Contributed by NM, 12-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑃 𝑄) (𝐹 ((𝑅 𝑆) 𝑊)))    &   𝐷 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐸 = ((𝑃 𝑄) (𝐷 ((𝑅 𝑇) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ (𝑃𝑄 ∧ (𝑅 (𝑃 𝑄) ∧ ¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ ¬ ∃𝑟𝐴𝑟 𝑊 ∧ (𝑃 𝑟) = (𝑄 𝑟)))) → 𝐺 = 𝐸)

Theoremcdlemesner 36450 Part of proof of Lemma E in [Crawley] p. 113. Utility lemma. (Contributed by NM, 13-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)       ((𝐾 ∈ HL ∧ (𝑅𝐴𝑆𝐴) ∧ (𝑅 (𝑃 𝑄) ∧ ¬ 𝑆 (𝑃 𝑄))) → 𝑆𝑅)

Theoremcdlemedb 36451 Part of proof of Lemma E in [Crawley] p. 113. Utility lemma. 𝐷 represents s2. (Contributed by NM, 20-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝐵 = (Base‘𝐾)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐴𝑆𝐴)) → 𝐷𝐵)

Theoremcdlemeda 36452 Part of proof of Lemma E in [Crawley] p. 113. Utility lemma. 𝐷 represents s2. (Contributed by NM, 13-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝐷 = ((𝑅 𝑆) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑅𝐴𝑅 (𝑃 𝑄) ∧ ¬ 𝑆 (𝑃 𝑄))) → 𝐷𝐴)

Theoremcdlemednpq 36453 Part of proof of Lemma E in [Crawley] p. 113. Utility lemma. 𝐷 represents s2. (Contributed by NM, 18-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝐷 = ((𝑅 𝑆) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴𝑄𝐴 ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ 𝑅 (𝑃 𝑄) ∧ ¬ 𝑆 (𝑃 𝑄))) → ¬ 𝐷 (𝑃 𝑄))

TheoremcdlemednuN 36454 Part of proof of Lemma E in [Crawley] p. 113. Utility lemma. 𝐷 represents s2. (Contributed by NM, 18-Nov-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑈 = ((𝑃 𝑄) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴𝑄𝐴 ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ 𝑅 (𝑃 𝑄) ∧ ¬ 𝑆 (𝑃 𝑄))) → 𝐷𝑈)

Theoremcdleme20zN 36455 Part of proof of Lemma E in [Crawley] p. 113. Utility lemma. (Contributed by NM, 17-Nov-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)       ((𝐾 ∈ HL ∧ (𝑅𝐴𝑆𝐴𝑇𝐴) ∧ (𝑆𝑇 ∧ ¬ 𝑅 (𝑆 𝑇))) → ((𝑆 𝑅) 𝑇) = (0.‘𝐾))

Theoremcdleme20y 36456 Part of proof of Lemma E in [Crawley] p. 113. Utility lemma. (Contributed by NM, 17-Nov-2012.) (Proof shortened by OpenAI, 25-Mar-2020.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)       ((𝐾 ∈ HL ∧ (𝑅𝐴𝑆𝐴𝑇𝐴) ∧ (𝑆𝑇 ∧ ¬ 𝑅 (𝑆 𝑇))) → ((𝑆 𝑅) (𝑇 𝑅)) = 𝑅)

Theoremcdleme19a 36457 Part of proof of Lemma E in [Crawley] p. 113, 5th paragraph on p. 114, 1st line. 𝐷 represents s2. In their notation, we prove that if r s t, then s2=(s t) w. (Contributed by NM, 13-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)       ((𝐾 ∈ HL ∧ (𝑅𝐴𝑆𝐴𝑇𝐴) ∧ (𝑅 (𝑃 𝑄) ∧ ¬ 𝑆 (𝑃 𝑄) ∧ 𝑅 (𝑆 𝑇))) → 𝐷 = ((𝑆 𝑇) 𝑊))

Theoremcdleme19b 36458 Part of proof of Lemma E in [Crawley] p. 113, 5th paragraph on p. 114, 1st line. 𝐷, 𝐹, 𝐺 represent s2, f(s), f(t). In their notation, we prove that if r s t, then s2 f(s) f(t). (Contributed by NM, 13-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ 𝑅𝐴) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑅 (𝑆 𝑇)))) → 𝐷 (𝐹 𝐺))

Theoremcdleme19c 36459 Part of proof of Lemma E in [Crawley] p. 113, 5th paragraph on p. 114, 1st line. 𝐷, 𝐹 represent s2, f(s). We prove f(s) s2. (Contributed by NM, 13-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ (𝑅𝐴𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄))) → 𝐹𝐷)

Theoremcdleme19d 36460 Part of proof of Lemma E in [Crawley] p. 113, 5th paragraph on p. 114. 𝐷, 𝐹, 𝐺 represent s2, f(s), f(t). We prove f(s) s2 = f(s) f(t). (Contributed by NM, 14-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ 𝑅𝐴) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑅 (𝑆 𝑇)))) → (𝐹 𝐷) = (𝐹 𝐺))

Theoremcdleme19e 36461 Part of proof of Lemma E in [Crawley] p. 113, 5th paragraph on p. 114, line 2. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). We prove f(s) s2=f(t) t2. (Contributed by NM, 14-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ 𝑅𝐴) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑅 (𝑆 𝑇)))) → (𝐹 𝐷) = (𝐺 𝑌))

Theoremcdleme19f 36462 Part of proof of Lemma E in [Crawley] p. 113, 5th paragraph on p. 114, line 3. 𝐷, 𝐹, 𝑁, 𝑌, 𝐺, 𝑂 represent s2, f(s), fs(r), t2, f(t), ft(r). We prove that if r s t, then ft(r) = ft(r). (Contributed by NM, 14-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ 𝑅𝐴) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑅 (𝑆 𝑇)))) → 𝑁 = 𝑂)

Theoremcdleme20aN 36463 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). (Contributed by NM, 14-Nov-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐴𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄))) → (𝑉 𝐷) = (((𝑆 𝑅) 𝑇) 𝑊))

Theoremcdleme20bN 36464 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, second line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). We show v s2 = v t2. (Contributed by NM, 15-Nov-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐴 ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄))) → (𝑉 𝐷) = (𝑉 𝑌))

Theoremcdleme20c 36465 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, second line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). (Contributed by NM, 15-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ 𝑇𝐴) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄))) → (𝐷 𝑌) = (((𝑅 𝑆) 𝑇) 𝑊))

Theoremcdleme20d 36466 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, second line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). (Contributed by NM, 17-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ 𝑅 (𝑃 𝑄))) → ((𝐹 𝐺) (𝐷 𝑌)) = 𝑉)

Theoremcdleme20e 36467 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, 4th line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). We show <f(s),s2,s> and <f(t),t2,t> are centrally perspective. (Contributed by NM, 17-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ 𝑅 (𝑃 𝑄))) → ((𝐹 𝐺) (𝐷 𝑌)) (𝑆 𝑇))

Theoremcdleme20f 36468 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, 4th line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). We show <f(s),s2,s> and <f(t),t2,t> are axially perspective. (Contributed by NM, 17-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ 𝑅 (𝑃 𝑄))) → ((𝐹 𝐷) (𝐺 𝑌)) (((𝐷 𝑆) (𝑌 𝑇)) ((𝑆 𝐹) (𝑇 𝐺))))

Theoremcdleme20g 36469 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, antepenultimate line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). (Contributed by NM, 18-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ 𝑅 (𝑃 𝑄))) → (((𝐷 𝑆) (𝑌 𝑇)) ((𝑆 𝐹) (𝑇 𝐺))) = (((𝑆 𝑅) (𝑇 𝑅)) ((𝑆 𝑈) (𝑇 𝑈))))

Theoremcdleme20h 36470 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, antepenultimate line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). (Contributed by NM, 18-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ (¬ 𝑅 (𝑆 𝑇) ∧ ¬ 𝑈 (𝑆 𝑇)))) → (((𝑆 𝑅) (𝑇 𝑅)) ((𝑆 𝑈) (𝑇 𝑈))) = (𝑅 𝑈))

Theoremcdleme20i 36471 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, antepenultimate line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). We show (f(s) s2) (f(t) t2) p q. (Contributed by NM, 18-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ (¬ 𝑅 (𝑆 𝑇) ∧ ¬ 𝑈 (𝑆 𝑇)))) → ((𝐹 𝐷) (𝐺 𝑌)) (𝑃 𝑄))

Theoremcdleme20j 36472 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). We show s2 t2. (Contributed by NM, 18-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ ¬ 𝑅 (𝑆 𝑇))) → 𝐷𝑌)

Theoremcdleme20k 36473 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, antepenultimate line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). (Contributed by NM, 20-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝑃𝐴𝑄𝐴) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄))) → (𝐹 𝐷) ≠ (𝑃 𝑄))

Theoremcdleme20l1 36474 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, penultimate line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t) respectively. (Contributed by NM, 20-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ (𝑅𝐴𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄))) → (𝐹 𝐷) ∈ (LLines‘𝐾))

Theoremcdleme20l2 36475 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, penultimate line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t) respectively. (Contributed by NM, 20-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ (¬ 𝑅 (𝑆 𝑇) ∧ ¬ 𝑈 (𝑆 𝑇)))) → ((𝐹 𝐷) (𝐺 𝑌)) ∈ 𝐴)

Theoremcdleme20l 36476 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, penultimate line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t) respectively. (Contributed by NM, 20-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ (¬ 𝑅 (𝑆 𝑇) ∧ ¬ 𝑈 (𝑆 𝑇)))) → ((𝐹 𝐷) (𝐺 𝑌)) = ((𝑃 𝑄) (𝐹 𝐷)))

Theoremcdleme20m 36477 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, penultimate line. 𝐷, 𝐹, 𝑁, 𝑌, 𝐺, 𝑂 represent s2, f(s), fs(r), t2, f(t), ft(r) respectively. We prove that if ¬ r s t and ¬ u s t, then fs(r) = ft(r). (Contributed by NM, 20-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ (¬ 𝑅 (𝑆 𝑇) ∧ ¬ 𝑈 (𝑆 𝑇)))) → 𝑁 = 𝑂)

Theoremcdleme20 36478 Combine cdleme19f 36462 and cdleme20m 36477 to eliminate ¬ 𝑅 (𝑆 𝑇) condition. (Contributed by NM, 28-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ ¬ 𝑈 (𝑆 𝑇))) → 𝑁 = 𝑂)

Theoremcdleme21a 36479 Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 28-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &   𝐴 = (Atoms‘𝐾)       (((𝐾 ∈ HL ∧ 𝑃𝐴𝑄𝐴) ∧ (𝑆𝐴 ∧ ¬ 𝑆 (𝑃 𝑄)) ∧ (𝑧𝐴 ∧ (𝑃 𝑧) = (𝑆 𝑧))) → 𝑆𝑧)

Theoremcdleme21b 36480 Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 28-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &   𝐴 = (Atoms‘𝐾)       (((𝐾 ∈ HL ∧ 𝑃𝐴𝑄𝐴) ∧ (𝑆𝐴𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄)) ∧ (𝑧𝐴 ∧ (𝑃 𝑧) = (𝑆 𝑧))) → ¬ 𝑧 (𝑃 𝑄))

Theoremcdleme21c 36481 Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 28-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴) ∧ (𝑆𝐴𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄)) ∧ (𝑧𝐴 ∧ (𝑃 𝑧) = (𝑆 𝑧))) → ¬ 𝑈 (𝑆 𝑧))

Theoremcdleme21at 36482 Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴) ∧ ((𝑆𝐴𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄)) ∧ 𝑈 (𝑆 𝑇)) ∧ (𝑧𝐴 ∧ (𝑃 𝑧) = (𝑆 𝑧))) → 𝑇𝑧)

Theoremcdleme21ct 36483 Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ 𝑈 (𝑆 𝑇))) ∧ ((𝑧𝐴 ∧ ¬ 𝑧 𝑊) ∧ (𝑃 𝑧) = (𝑆 𝑧))) → ¬ 𝑈 (𝑇 𝑧))

Theoremcdleme21d 36484 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 115, 3rd line. 𝐷, 𝐹, 𝑁, 𝐸, 𝐵, 𝑍 represent s2, f(s), fs(r), z2, f(z), fz(r) respectively. We prove fs(r) = fz(r). (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐵 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝐸 = ((𝑅 𝑧) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑍 = ((𝑃 𝑄) (𝐵 𝐸))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ (𝑃𝑄 ∧ (¬ 𝑆 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ ((𝑧𝐴 ∧ ¬ 𝑧 𝑊) ∧ (𝑃 𝑧) = (𝑆 𝑧)))) → 𝑁 = 𝑍)

Theoremcdleme21e 36485 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 115, 3rd line. 𝑌, 𝐺, 𝑂, 𝐸, 𝐵, 𝑍 represent s2, f(s), fs(r), z2, f(z), fz(r) respectively. We prove that if u s z, then ft(r) = fz(r). (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐵 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝐸 = ((𝑅 𝑧) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑍 = ((𝑃 𝑄) (𝐵 𝐸))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄))) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑈 (𝑆 𝑇)) ∧ ((𝑧𝐴 ∧ ¬ 𝑧 𝑊) ∧ (𝑃 𝑧) = (𝑆 𝑧)))) → 𝑂 = 𝑍)

Theoremcdleme21f 36486 Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐵 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝐸 = ((𝑅 𝑧) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑍 = ((𝑃 𝑄) (𝐵 𝐸))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄))) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑈 (𝑆 𝑇)) ∧ ((𝑧𝐴 ∧ ¬ 𝑧 𝑊) ∧ (𝑃 𝑧) = (𝑆 𝑧)))) → 𝑁 = 𝑂)

Theoremcdleme21g 36487 Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄))) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑈 (𝑆 𝑇)) ∧ ((𝑧𝐴 ∧ ¬ 𝑧 𝑊) ∧ (𝑃 𝑧) = (𝑆 𝑧)))) → 𝑁 = 𝑂)

Theoremcdleme21h 36488* Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄))) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑈 (𝑆 𝑇)))) → (∃𝑧𝐴𝑧 𝑊 ∧ (𝑃 𝑧) = (𝑆 𝑧)) → 𝑁 = 𝑂))

Theoremcdleme21i 36489* Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄))) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑈 (𝑆 𝑇)))) → (∃𝑟𝐴𝑟 𝑊 ∧ (𝑃 𝑟) = (𝑄 𝑟)) → 𝑁 = 𝑂))

Theoremcdleme21j 36490* Combine cdleme20 36478 and cdleme21i 36489 to eliminate 𝑈 (𝑆 𝑇) condition. (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ ∃𝑟𝐴𝑟 𝑊 ∧ (𝑃 𝑟) = (𝑄 𝑟)))) → 𝑁 = 𝑂)

Theoremcdleme21 36491 Part of proof of Lemma E in [Crawley] p. 113, 3rd line on p. 115. 𝐷, 𝐹, 𝑁, 𝑌, 𝐺, 𝑂 represent s2, f(s), fs(r), t2, f(t), ft(r) respectively. Combine cdleme18d 36449 and cdleme21j 36490 to eliminate existence condition, proving fs(r) = ft(r) with fewer conditions. (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)))) → 𝑁 = 𝑂)

Theoremcdleme21k 36492 Eliminate 𝑆𝑇 condition in cdleme21 36491. (Contributed by NM, 26-Dec-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ (𝑃𝑄 ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)))) → 𝑁 = 𝑂)

Theoremcdleme22aa 36493 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 3rd line on p. 115. Show that t v = p q implies v = u. (Contributed by NM, 2-Dec-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴𝑃𝑄) ∧ (𝑉𝐴𝑉 𝑊𝑉 (𝑃 𝑄))) → 𝑉 = 𝑈)

Theoremcdleme22a 36494 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 3rd line on p. 115. Show that t v = p q implies v = u. (Contributed by NM, 30-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴𝑇𝐴) ∧ ((𝑉𝐴𝑉 𝑊) ∧ 𝑃𝑄 ∧ (𝑇 𝑉) = (𝑃 𝑄))) → 𝑉 = 𝑈)

Theoremcdleme22b 36495 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 5th line on p. 115. Show that t v =/= p q and s p q implies ¬ t p q. (Contributed by NM, 2-Dec-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)       (((𝐾 ∈ HL ∧ (𝑆𝐴𝑇𝐴𝑆𝑇)) ∧ (𝑃𝐴𝑄𝐴𝑃𝑄) ∧ (𝑉𝐴 ∧ ((𝑇 𝑉) ≠ (𝑃 𝑄) ∧ 𝑆 (𝑇 𝑉) ∧ 𝑆 (𝑃 𝑄)))) → ¬ 𝑇 (𝑃 𝑄))

Theoremcdleme22cN 36496 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 5th line on p. 115. Show that t v =/= p q and s p q implies ¬ v p q. (Contributed by NM, 3-Dec-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ 𝑇𝐴 ∧ (𝑉𝐴𝑉 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (𝑆 (𝑇 𝑉) ∧ 𝑆 (𝑃 𝑄)) ∧ (𝑇 𝑉) ≠ (𝑃 𝑄))) → ¬ 𝑉 (𝑃 𝑄))

Theoremcdleme22d 36497 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 9th line on p. 115. (Contributed by NM, 4-Dec-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑉𝐴𝑉 𝑊)) ∧ (𝑆𝑇𝑆 (𝑇 𝑉))) → 𝑉 = ((𝑆 𝑇) 𝑊))

Theoremcdleme22e 36498 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 4th line on p. 115. 𝐹, 𝑁, 𝑂 represent f(z), fz(s), fz(t) respectively. When t v = p q, fz(s) fz(t) v. (Contributed by NM, 6-Dec-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑆 𝑧) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝐹 ((𝑇 𝑧) 𝑊)))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ (𝑆𝐴𝑇𝐴)) ∧ ((𝑉𝐴𝑉 𝑊) ∧ (𝑃𝑄 ∧ (𝑇 𝑉) = (𝑃 𝑄)) ∧ (𝑧𝐴 ∧ ¬ 𝑧 𝑊))) → 𝑁 (𝑂 𝑉))

Theoremcdleme22eALTN 36499 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 4th line on p. 115. 𝐹, 𝑁, 𝑂 represent f(z), fz(s), fz(t) respectively. When t v = p q, fz(s) fz(t) v. (Contributed by NM, 6-Dec-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑦 𝑈) (𝑄 ((𝑃 𝑦) 𝑊)))    &   𝐺 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑆 𝑦) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝐺 ((𝑇 𝑧) 𝑊)))       (((𝐾 ∈ HL ∧ 𝑊𝐻𝑇𝐴) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ 𝑃𝑄) ∧ (𝑆𝐴 ∧ (𝑉𝐴𝑉 𝑊 ∧ (𝑇 𝑉) = (𝑃 𝑄)) ∧ ((𝑦𝐴 ∧ ¬ 𝑦 𝑊) ∧ (𝑧𝐴 ∧ ¬ 𝑧 𝑊)))) → 𝑁 (𝑂 𝑉))

Theoremcdleme22f 36500 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 6th and 7th lines on p. 115. 𝐹, 𝑁 represent f(t), ft(s) respectively. If s t v, then ft(s) f(t) v. (Contributed by NM, 6-Dec-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑆 𝑇) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ 𝑇𝐴 ∧ (𝑉𝐴𝑉 𝑊)) ∧ (𝑆𝑇𝑆 (𝑇 𝑉))) → 𝑁 (𝐹 𝑉))

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