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| Mirrors > Home > MPE Home > Th. List > Mathboxes > eliminable-abelab | Structured version Visualization version GIF version | ||
| Description: A theorem used to prove the base case of the Eliminability Theorem (see section comment): abstraction belongs to abstraction. (Contributed by BJ, 30-Apr-2024.) (Proof modification is discouraged.) (New usage is discouraged.) |
| Ref | Expression |
|---|---|
| eliminable-abelab | ⊢ ({𝑥 ∣ 𝜑} ∈ {𝑦 ∣ 𝜓} ↔ ∃𝑧(∀𝑡(𝑡 ∈ 𝑧 ↔ [𝑡 / 𝑥]𝜑) ∧ [𝑧 / 𝑦]𝜓)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | dfclel 2845 | . 2 ⊢ ({𝑥 ∣ 𝜑} ∈ {𝑦 ∣ 𝜓} ↔ ∃𝑧(𝑧 = {𝑥 ∣ 𝜑} ∧ 𝑧 ∈ {𝑦 ∣ 𝜓})) | |
| 2 | eliminable-veqab 37386 | . . . 4 ⊢ (𝑧 = {𝑥 ∣ 𝜑} ↔ ∀𝑡(𝑡 ∈ 𝑧 ↔ [𝑡 / 𝑥]𝜑)) | |
| 3 | eliminable-velab 37385 | . . . 4 ⊢ (𝑧 ∈ {𝑦 ∣ 𝜓} ↔ [𝑧 / 𝑦]𝜓) | |
| 4 | 2, 3 | anbi12i 639 | . . 3 ⊢ ((𝑧 = {𝑥 ∣ 𝜑} ∧ 𝑧 ∈ {𝑦 ∣ 𝜓}) ↔ (∀𝑡(𝑡 ∈ 𝑧 ↔ [𝑡 / 𝑥]𝜑) ∧ [𝑧 / 𝑦]𝜓)) |
| 5 | 4 | exbii 1875 | . 2 ⊢ (∃𝑧(𝑧 = {𝑥 ∣ 𝜑} ∧ 𝑧 ∈ {𝑦 ∣ 𝜓}) ↔ ∃𝑧(∀𝑡(𝑡 ∈ 𝑧 ↔ [𝑡 / 𝑥]𝜑) ∧ [𝑧 / 𝑦]𝜓)) |
| 6 | 1, 5 | bitri 278 | 1 ⊢ ({𝑥 ∣ 𝜑} ∈ {𝑦 ∣ 𝜓} ↔ ∃𝑧(∀𝑡(𝑡 ∈ 𝑧 ↔ [𝑡 / 𝑥]𝜑) ∧ [𝑧 / 𝑦]𝜓)) |
| Colors of variables: wff setvar class |
| Syntax hints: ↔ wb 209 ∧ wa 400 ∀wal 1565 = wceq 1567 ∃wex 1806 [wsb 2097 ∈ wcel 2149 {cab 2747 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1822 ax-4 1836 ax-5 1937 ax-6 1994 ax-7 2035 ax-8 2151 ax-9 2159 ax-ext 2741 |
| This theorem depends on definitions: df-bi 210 df-an 401 df-ex 1807 df-clab 2748 df-cleq 2761 df-clel 2844 |
| This theorem is referenced by: (None) |
| Copyright terms: Public domain | W3C validator |