Theorem hadifpOLD 1638

Description: Obsolete version of hadifp 1637 as of 10-Aug-2026. (Contributed by BJ, 11-Aug-2020.) (Proof modification is discouraged.) (New usage is discouraged.)

Assertion

Ref	Expression
hadifpOLD	⊢ (hadd(𝜑, 𝜓, 𝜒) ↔ if-(𝜑, (𝜓 ↔ 𝜒), (𝜓 ⊻ 𝜒)))

Proof of Theorem hadifpOLD

Step	Hyp	Ref	Expression
1		had1OLD 1635	. 2 ⊢ (𝜑 → (hadd(𝜑, 𝜓, 𝜒) ↔ (𝜓 ↔ 𝜒)))
2		had0OLD 1636	. 2 ⊢ (¬ 𝜑 → (hadd(𝜑, 𝜓, 𝜒) ↔ (𝜓 ⊻ 𝜒)))
3	1, 2	casesifp 1094	1 ⊢ (hadd(𝜑, 𝜓, 𝜒) ↔ if-(𝜑, (𝜓 ↔ 𝜒), (𝜓 ⊻ 𝜒)))

This proof depends on syntax axioms:   ↔ wb 209  if-wif 1078   ⊻ wxo 1541  haddwhad 1623

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-ifp 1079  df-xor 1542  df-had 1624

This theorem is used by: (None)