Theorem casesifp 1078

Description: Version of cases 1042 expressed using if-. Case disjunction according to the value of 𝜑. One can see this as a proof that the two hypotheses characterize the conditional operator for propositions. For the converses, see ifptru 1075 and ifpfal 1076. (Contributed by BJ, 20-Sep-2019.)

Hypotheses

Ref	Expression
casesifp.1	⊢ (𝜑 → (𝜓 ↔ 𝜒))
casesifp.2	⊢ (¬ 𝜑 → (𝜓 ↔ 𝜃))

Assertion

Ref	Expression
casesifp	⊢ (𝜓 ↔ if-(𝜑, 𝜒, 𝜃))

Proof of Theorem casesifp

Step	Hyp	Ref	Expression
1		casesifp.1	. . 3 ⊢ (𝜑 → (𝜓 ↔ 𝜒))
2		casesifp.2	. . 3 ⊢ (¬ 𝜑 → (𝜓 ↔ 𝜃))
3	1, 2	cases 1042	. 2 ⊢ (𝜓 ↔ ((𝜑 ∧ 𝜒) ∨ (¬ 𝜑 ∧ 𝜃)))
4		df-ifp 1063	. 2 ⊢ (if-(𝜑, 𝜒, 𝜃) ↔ ((𝜑 ∧ 𝜒) ∨ (¬ 𝜑 ∧ 𝜃)))
5	3, 4	bitr4i 281	1 ⊢ (𝜓 ↔ if-(𝜑, 𝜒, 𝜃))

Syntax hints:  ¬ wn 3   → wi 4   ↔ wb 209   ∧ wa 399   ∨ wo 846  if-wif 1062

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 210  df-an 400  df-or 847  df-ifp 1063

This theorem is referenced by:  hadifp  1611  cadifp  1626  wl-1xor  35276  wl-1mintru1  35282  brif1  39780  brif2  39781  brif12  39782