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| Mirrors > Home > NFE Home > Th. List > sbsbc | Unicode version | ||
| Description: Show that df-sb 1649 and df-sbc 3048 are equivalent when the class term |
| Ref | Expression |
|---|---|
| sbsbc |
|
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | eqid 2353 |
. 2
| |
| 2 | dfsbcq2 3050 |
. 2
| |
| 3 | 1, 2 | ax-mp 5 |
1
|
| Colors of variables: wff setvar class |
| Syntax hints: |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1546 ax-5 1557 ax-17 1616 ax-9 1654 ax-8 1675 ax-11 1746 ax-ext 2334 |
| This theorem depends on definitions: df-bi 177 df-an 360 df-ex 1542 df-clab 2340 df-cleq 2346 df-clel 2349 df-sbc 3048 |
| This theorem is referenced by: spsbc 3059 sbcid 3063 sbcco 3069 sbcco2 3070 sbcie2g 3080 eqsbc1 3086 sbcralt 3119 csbid 3144 sbnfc2 3197 csbabg 3198 cbvralcsf 3199 cbvreucsf 3201 cbvrabcsf 3202 |
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